SOLUTION: nina is four years older than jennifer. in seven years, she will be twice as jennifer was in 5 years ago. Find the present ages of Nina and Jennifer

Algebra.Com
Question 1059206: nina is four years older than jennifer. in seven years, she will be twice as jennifer was in 5 years ago. Find the present ages of Nina and Jennifer


Answer by Boreal(15235)   (Show Source): You can put this solution on YOUR website!
Nina=x
Jennifer=x-4
In 7 years, Nina will be x+7 years old and that is 2*(x-9), which is x-4, Jennifer's age, minus 5
x+7=2(x-9)
x+7=2x-18
x=25 years for Nina
Jennifer is 21 years
In 7 years, Nina will be 32, which is twice the 16 that Jennifer was 5 years ago.

RELATED QUESTIONS

Jennifer is 6 years older than Sue. In 4 years, she will be twice as old as Sue was 5... (answered by edjones)
Jennifer is 6 years older than Sue. In 4 years, She will be twice as old as Sue was 5... (answered by richwmiller)
jennifer is 6 years older than sue. in 4 years, she will be twice as old as sue was 5... (answered by oberobic)
Jennifer is 6 years older than Sue. In 4 years, she will be twice as old as Sue was 5... (answered by LynnMomo)
Please help! I'm totally stuck... Jennifer is four years older than her sister, Sue. In (answered by checkley77,scott8148)
Help me solv this? Jennifer is six years older than Sue. In four years she will be twice (answered by ptaylor)
How do I solve by using a system of two equations in two variables? Jennifer is 6... (answered by checkley77)
This question is from a worksheet. We do not have a textbook. Jennifer is 6 years older (answered by josmiceli)
jennifer is one-fourth her father's age. In twelve years, Jennifer will be the same age... (answered by mathslover)