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Four times the present Age of Helen is three times the present age of Abel.
Ten years ago three times the age of Helen was six less than the age Abel. What is the present age of each?
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4H = 3A, (1)
3*(H-10) = (A-10) - 6. (2)
Simplify (2):
3H - 30 = A - 16, or
3H - A = 30 - 16, or
3H - A = 14. (3)
Now from (3) express A = 3H -14 and substitute it into (1). You will get
4H = 3*(3H-14),
4H = 9H - 42,
42 = 9H - 4H,
5H = 42 ---> H = .
Answer. Wrong data. The right place of this problem and the post is in the TRASH section.