SOLUTION: Father is 16 years older than his son. 6 years ago the father was 3 times his sons age. How are are both the son and his father now?

Question 1058027: Father is 16 years older than his son. 6 years ago the father was 3 times his sons age. How are are both the son and his father now?
Answer by solve_for_x(190) (Show Source): You can put this solution on YOUR website!
Let x represent the son's age.

The father's current age is then x + 16.

Six years ago, the father's age was (x + 16) - 6 = x + 10.

Six years ago, the son's age was x - 6.

Since the father's age then was 3 times the son's age you can write the following equation:

x + 10 = 3(x - 6)

x + 10 = 3x - 18

3x - 18 = x + 10

3x - x - 18 = 10

2x - 18 = 10

2x = 10 + 18

2x = 28

x = 14

Thus, the son's current age is 14, and the father's current age is 14 + 16 = 30.
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