SOLUTION: The ages of a brother and the younger sisters sum to 44 years. In five years the brother will be twice as old as his sister. Find the age of the brother and sister.

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Question 1057373: The ages of a brother and the younger sisters sum to 44 years. In five years the brother will be twice as old as his sister. Find the age of the brother and sister.
Answer by ikleyn(52803)   (Show Source): You can put this solution on YOUR website!
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The ages of a brother and the younger sisters sum to 44 years. In five years the brother will be twice as old as his sister.
Find the age of the brother and sister.
~~~~~~~~~~~~~~~~~~~~~~

Let B be the brother's present age. 
Then the sister's present age is 44-B.

In 5 years the brother will be (B+5) years old. 
while sister will be 44-B + 5.

We are given that

B+5 = 2(44-B+5).

Simplify and solve for B:

B + 5 = 88 - 2B + 10,

B + 2B = 88+10-5,

3B = 93,

B =  = 31.

Answer. The brother's present age is 31 year. The sister is 44-31 = 13 years old.

There is a bunch of lessons on age word problems
    - Age problems and their solutions
    - A fresh formulation of a traditional age problem
    - Really intricate age word problem
    - Selected age word problems from the archive
in this site.

Read them and become an expert in solving age problems.

Also, you have this free of charge online textbook in ALGEBRA-I in this site
    - ALGEBRA-I - YOUR ONLINE TEXTBOOK.

The referred lessons are the part of this online textbook under the topic "Age word problems".


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