SOLUTION: The ages of three sisters are consecutive odd integers. Twice the age of then age of the youngest sister is one less than the oldest sisters? Only an algebraic solution will be acc

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Question 1055558: The ages of three sisters are consecutive odd integers. Twice the age of then age of the youngest sister is one less than the oldest sisters? Only an algebraic solution will be accepted. Write a let statement too.
Answer by ikleyn(52781)   (Show Source): You can put this solution on YOUR website!
.
The ages of three sisters are consecutive odd integers. Twice the age of the youngest sister is one less
than the oldest sisters? Only an algebraic solution will be accepted. Write a let statement too.
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ 

The sisters ages are n, n+2, and n+4.

The equation is

2n = (n+4) - 1.

2n = n +3  --->  n = 3.

Answer.  3, 5 and 7 years.

It seems to me that the person who understand the meaning of the words "odd" and "consecutive" must solve it on his/her own
without any difficulties.


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