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A father is three times as old as the son. Nine years ago the father was four times as old as the son find the present ages.
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F = 3S, (1) ("A father is three times as old as the son")
F-9 = 4*(S-9) (2) ("Nine years ago the father was four times as old as the son")
Substitute (1) into (2). You will get
3S-9 = 4(S-9),
3S-9 = 4S - 36 ---> S = 27.
The son is 27 years old now. The father is 3*27 = 81 years old now.
Answer. The son is 27 years old now. The father is 81 years old now.
There is a bunch of lessons on age word problems
- Age problems and their solutions
- A fresh formulation of a traditional age problem
- Really intricate age word problem
- Selected age word problems from the archive
- Age problem for the day of April, 1
- OVERVIEW of lessons on age problems
in this site.
Read them and become an expert in solving age problems.
Also, you have this free of charge online textbook in ALGEBRA-I in this site
- ALGEBRA-I - YOUR ONLINE TEXTBOOK.
The referred lessons are the part of this online textbook under the topic "Age problems".