SOLUTION: five years ago a mother was twice as old ss her son. in 6 yrs time, the sum of their age will be 82. find there percentage age ??

Question 1052164: five years ago a mother was twice as old ss her son. in 6 yrs time, the sum of their age will be 82. find there percentage age ??
Found 2 solutions by jorel555, advanced_Learner:
Answer by jorel555(1290) (Show Source): You can put this solution on YOUR website!
Let s be the age of the son five years ago. Then the mother would be 2s. So:
s+5+6+2s+5+6=82
3s=60
s=20
s+5=25
2s+5=45
45/25=1.8 is the ratio of their ages right now. ☺☺☺☺
Answer by advanced_Learner(501) (Show Source): You can put this solution on YOUR website!
m and s age now
age five years ago
m-5
s-5
age six years from no
m+6
s+6

=
=
re-arrange
=
=

Solved by pluggable solver: Linear System solver (using determinant)

Solve:

Any system of equations:

has solution

or

(m=45, s=25}

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