.
Mother is thrice as old as her son, ten years from now mother will be twice as old as her son.
How old are they?
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M = 3S, (1)
M + 10 = 2*(S+10). (2)
Substitute (1) into (2). You will get
3S + 10 = 2*(S+10) ---> 3S + 10 = 2S + 20 ---> S = 10.
Answer. The son is 10 years now. The mother's present age is 30 years.
There is a bunch of lessons on age word problems
- Age problems and their solutions
- A fresh formulation of a traditional age problem
- Really intricate age word problem
- Selected age word problems from the archive
- Age problem for the day of April, 1
- OVERVIEW of lessons on age problems
in this site.
Read them and become an expert in solving age problems.
Also, you have this free of charge online textbook in ALGEBRA-I in this site
- ALGEBRA-I - YOUR ONLINE TEXTBOOK.
It contains a lot of other word problems and many other interesting and useful things.