SOLUTION: Jack is 4 times as old as Lacy. 10 years ago the sum of their ages was 40. How old are they now?

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Question 1051454: Jack is
4 times as old as Lacy.
10 years ago the sum of their ages was
40. How old are they now?
Answer by Edwin McCravy(20056)   (Show Source): You can put this solution on YOUR website!


Jack is 4 times as old as Lacy.
J = 4L
10 years ago...
10 years ago Jack was J-10
10 years ago Lacy was L-10
...the sum of their ages was 40.
J-10 + L-10 = 40 

Simplify that and substitute 4L for J,
then solve the equation for L. That will be
Lacy's age. Then Substitute what you get for 
L in J = 4L to find Jack's age.

Edwin
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