Question 1049918: The sum of the ages of two cosins is 15. In 3 years the older cousin will be twice as old as the younger cousin. How old is the cousin now? Found 2 solutions by jorel555, advanced_Learner:Answer by jorel555(1290) (Show Source): You can put this solution on YOUR website! Let m and n represent the two cousins. Then m+n=15. In three years n will be twice as old as m, so 2(m+3)=n+3. So:
2m+6=n+3
2m+3=n
m+2m+3=15
3m=12
m=4
n=11
The older cousin is now 11 years old. ☺☺☺☺ Answer by advanced_Learner(501) (Show Source): You can put this solution on YOUR website! = =
Solve: We'll use substitution. After moving 1*y to the right, we get: , or . Substitute that
into another equation: and simplify: So, we know that y=11. Since , x=4.