SOLUTION: A father is 46 years older than his son. In 10 years he'll be twice as old as his son what are their present ages
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Question 1046856: A father is 46 years older than his son. In 10 years he'll be twice as old as his son what are their present ages
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
A father is 46 years older than his son. In 10 years he'll be twice as old as his son what are their present ages
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F = S + 46
F+10 = 2(S+10)
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Substitute for "F" and solve for "S"::
S + 46 + 10 = 2S + 20
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S = 36 yrs (son's age now)
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F = S + 46 = 36+46 = 82 yrs (Father's age now)
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Cheers,
Stan H.
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