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Jack is 2 times as old as Lacy. 7 years ago the sum of their ages was 28. How old are they now?
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J = 2L, (1) ( "Jack is 2 times as old as Lacy" )
Since "7 years ago the sum of their ages was 28", then the sum of their ages now is 28 + 7 + 7 = 42 now:
J + L = 42. (2)
Substitute (1) into (2. You will get
2L + l = 42,
3L = 42,
L = = 14.
Answer. Lacy is 14 years now. Jack is 14*2 = 28 years old now.
For many other solved age problems see the lessons
- Age problems and their solutions
- A fresh formulation of a traditional age problem
- Really intricate age word problem
- Selected age word problems from the archive
- Age problem for the day of April, 1
in this site.
Read them and become an expert in solution age problems.
Also, you have this free of charge online textbook in ALGEBRA-I in this site
- ALGEBRA-I - YOUR ONLINE TEXTBOOK.
which includes many other word problems and many other interesting and useful things.