SOLUTION: The age of Radhika's mother is square the age of Radhika. Five years hence, mother will be 3 times her age. The difference of their ages will be:

Question 1045432: The age of Radhika's mother is square the age of Radhika. Five years hence, mother will be 3 times her age. The difference
of their ages will be:
Found 2 solutions by Alan3354, jorel555:
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
The age of Radhika's mother is square the age of Radhika. Five years hence, mother will be 3 times her age. The difference
of their ages will be:
--------------
M = R^2
M+5 = 3(R+5)
----
Sub for M
R^2+5 = 3R+15
R^2 - 3R - 10 = 0
(R-5)*(R+2) = 0
R = 5
etc
Answer by jorel555(1290) (Show Source): You can put this solution on YOUR website!
Let r represent Radhika. Then Radhika's mother is r�. So
3(r+5)=r�+5
3r+15=r�+5
r�-3r-10=0
(r+2)(r-5)=0
r=5
r+5=10
r�+5=30
In 5 years, the difference in their ages will be 20 years.☺☺☺☺
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