SOLUTION: Jose is 3 times as old as Wally. Five years from now, The sum of their ages is 42. How old are they now?

Question 1043017: Jose is 3 times as old as Wally. Five years from now, The sum of their ages is 42. How old are they now?
Answer by ikleyn(52776) (Show Source): You can put this solution on YOUR website!
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Jose is 3 times as old as Wally. Five years from now, The sum of their ages is 42. How old are they now?
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Let J = Jose's age now; W = Wally's age now. Then

J = 3W,               (1)     ( "Jose is 3 times as old as Wally" )
(J+5) + (W+5) = 42.   (2)     ( "Five years from now, The sum of their ages is 42" )

Simplify 2):

J + W + 10 = 42,   or

J + W = 42-10 = 32.

Now substitute J= 3W from (1) into the last equation. You will have

3W + W = 32.

Can you complete the solution from this point?

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