SOLUTION: 5 years ago a man was 7 times as old as his son. 5 years hence , the father will be three times as old as his son. Find their present ages.

Question 1042959: 5 years ago a man was 7 times as old as his son. 5 years hence , the father will be three times as old as his son. Find their present ages.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
5 years ago a man was 7 times as old as his son. 5 years hence , the father will be three times as old as his son. Find their present ages.
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f-5 = 7(s-5)
f+5 = 3(s+5)
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Simplify::
f - 7s = -30
f - 3s = 10
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Subtract and solve for "s":
4s = 40
son's age = 10 yrs
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Solve for "f":
f - 5 = 7(s-5)
f - 5 = 7(10-5)
f = 7*5+5 = 40 years (father's age)
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Cheers,
Stan H.

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