SOLUTION: Joey is twice as old as Glaiza while Priam is 24 years younger than Joey.If half of Joey's age six years ago was three less than one half the sum of Glaiza's age in four years and

Question 1040368: Joey is twice as old as Glaiza while Priam is 24 years younger than Joey.If half of Joey's age six years ago was three less than one half the sum of Glaiza's age in four years and Priam's present age,find the ages of each.

Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!

Let j = Joe's age
let g = Glaze's age
let p = Prim's age
:
Write an equation for each statment
:
Joey is twice as old as Glaiza
j = 2g
or
g = .5j
while Priam is 24 years younger than Joey.
p = j - 24
If half of Joey's age six years ago was three less than one half the sum of Glaiza's age in four years and Priam's present age,
(j-6) = ((g+4) + p) - 3
multiply both sides by 2 to get rid of the fractions
j - 6 = (g+4) + p - 2(3)
j - 6 = g + p + 4 - 6
Add 6 to both sides
j = g + p + 4
Replace g with .5j; replace p with (j-24)
j = .5j + (j-24) + 4
j -.5j - j = - 24 + 4
-.5j = -20
j = -20/-.5
j = +40 yrs is Joe's age
then
p = 40 - 24
p = 16 yrs is Prim's age
and
g = .5(40)
g = 20 yrs is Glaze's age
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