SOLUTION: The age of a father is 10 less than the sum of the ages of his two sons. 7 years ago his age was 3 times the sum of the ages of his sons find their present ages

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Question 1035760: The age of a father is 10 less than the sum of the ages of his two sons. 7 years ago his age was 3 times the sum of the ages of his sons find their present ages
Found 2 solutions by fractalier, ikleyn:
Answer by fractalier(6550)   (Show Source): You can put this solution on YOUR website!
f = s - 10
f-7 = 3(s-7)
s-10 - 7 = 3s - 21
s - 17 = 3s - 21
s = 2
Impossible. The father cannot be -8 years old.
You have posted the wrong question as it is written. Please check it.
Answer by ikleyn(52798)   (Show Source): You can put this solution on YOUR website!
.
The age of a father is 10 less than the sum of the ages of his two sons. 7 years ago his age was 3 times
the sum of the ages of his sons find their present ages
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ 

f = s - 10,       (1)
f-7 = 3*(s-14).   (2)     <<<<--- "14" must be distracted, not "7" !

--->  (s-10) -7 = 3s - 42

s - 17 = 3s - 42,

2s = 42 - 17 = 25.


s = 12.5



Hello, the author! 


1. Change the data in your problem to allow "s" to be integer.


2. From the given data it is impossible to determine the age of the two sons. Too few data.


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