SOLUTION: maths a woman's son is 2 years older than her daughter.Her age is 3 times the sum of the ages of the children.After 5 years she will be 47 years old.Find the present ages of the c

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Question 1023543: maths a woman's son is 2 years older than her daughter.Her age is 3 times the sum of the ages of the children.After 5 years she will be 47 years old.Find the present ages of the children?
Answer by ikleyn(52776)   (Show Source): You can put this solution on YOUR website!
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maths a woman's son is 2 years older than her daughter.Her age is 3 times the sum of the ages of the children.
After 5 years she will be 47 years old. Find the present ages of the children?
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ 

The present age of the woman is 47 - 5 = 42.

Since the woman's age is 3 times the sum of the ages of the children, this sum is  = 14.

So for children ages you have two equations:

s + d = 14,
s - d = 2.

Every time when you see two equations like these, add them.
You will get

2s = 14 + 2,
2s = 16,

s =  = 8.

Thus sun is 8 years now. The daughter is 8 - 2 = 6 years.


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