SOLUTION: Jeffrey's father is four times as old as he is the sum of their ages is 50 years how old is each

Algebra.Com
Question 1022152: Jeffrey's father is four times as old as he is the sum of their ages is 50 years how old is each
Answer by addingup(3677)   (Show Source): You can put this solution on YOUR website!
F = 4J (four times Jeffrey = father's age)
F+J = 50 substitute for F:
4J+J = 50
5j = 50 divide both sides by 5 to get your answer

RELATED QUESTIONS

a father is four times as old as his son. In three years the sum of their ages will be... (answered by rwm)
a father is 3 times as old as his son 3 years ago the sum of their ages was 50.How old is (answered by Alan3354)
A father is 3 times as old as his son. 3 years ago, the sum of their ages was 50. How old (answered by Boreal)
three years ago, jeffrey was twice as old as michael is now. in nine years, jeffrey will... (answered by stanbon)
If stephanie father is 4 times as old as stephanie and the sum of both ages is 50 years... (answered by checkley71,lesfarley)
Jack’s father is three times as old as Jack. Five years ago, the sum of there ages was... (answered by josgarithmetic,MathLover1)
13. John is ¼ as old as his father. In 8 years time , the sum of their ages will be... (answered by ewatrrr)
12 years old Ryan is three times as old as his brother Jeffrey,how old Will Ryan be when... (answered by jorel1380)
Robert’s father is four times as old as Robert. After five years, Robert’s father... (answered by josgarithmetic)