The sum of the ages of Ron and Iezus is 92. In 6 years, the difference of their ages is 24. Given that Ron is older than Iezus, how old is each now?
Let Ron's age be R, and Iezus', I
Then: R + I = 92 -------- eq (i)
Once their ages differ by 24, it doesn't matter which year they're in, their ages will
always differ by 24, and since Ron is older, we get: R = 24 + I --------- eq (ii)
24 + I + I = 92 --------- Substituting 24 + I for R in (i)
2I = 92 - 24
2I = 68
I, or Iezus' age = , or
R = 24 + 34 --------- Substituting 34 for I in eq (ii)
R, or Ron's age =