SOLUTION: Mary's age is 5 times Jose's age. The sum of their ages is 18. How old is each?

Algebra.Com
Question 1015574: Mary's age is 5 times Jose's age. The sum of their ages is 18. How old is each?
Answer by ikleyn(52787)   (Show Source): You can put this solution on YOUR website!
.
Mary's age is 5 times Jose's age. The sum of their ages is 18. How old is each?
------------------------------------------------

Mary is 15, Joe is 3 ears old. 

Your equation is 

5J + J = 18,

or

6J = 18.

Surely, J = 3.


RELATED QUESTIONS

Carole’s age is five times Joe’s age. The sum of their ages is 18. How old are Carole (answered by josgarithmetic,ikleyn)
Mary is the younger than her sister Joan. The sum of their age is 15. Twice Joan’s age... (answered by marcsam823)
Mary is the younger than her sister Joan. The sum of their age is 15. Twice Joan’s age... (answered by checkley77)
Jean’s age is 5 years more than twice Lucy’s age. The sum of their ages is 29. How old... (answered by ikleyn)
Jack is 3 years younger than twice Mary's age . If the sum of their ages is 90 , how old... (answered by ewatrrr)
Lee’s mother’s age is two more than three times Lee’s age, the sum of their ages is (answered by ikleyn)
Jack’s age is 5 less than three times Rebecca’s age. The sum of their ages is 75.... (answered by ikleyn)
Mary's age is 5 times Joe's age. the sum of their age is 18. How old is each person? (answered by Alan3354)
Angie's age is no less than 6 more than Rose's age. The sum of their ages is greater than (answered by josgarithmetic)