SOLUTION: Andrew is two years older that Bianca if their ages have a sum of 28 years, how old is each one?

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Question 1014820: Andrew is two years older that Bianca if their ages have a sum of 28 years, how old is each one?
Found 2 solutions by Alan3354, macston:
Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
Andrew is two years older that Bianca if their ages have a sum of 28 years, how old is each one?
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A + B = 28
A - B = 2
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Answer by macston(5194)   (Show Source): You can put this solution on YOUR website!
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A=Andrew's age; B=Bianca's age
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A=B+2yrs . Use this to substitute for A below
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A+B=28 yrs . Substitute for A from above.
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(B+2yrs)+B=28yrs . Subtract 2 yrs from each side.
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2B=26 yrs . Divide each side by 2.
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B=13 yrs
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ANSWER 1: Bianca is 13 years old.
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A=B+2yrs=13yrs+2yrs=15yrs
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ANSWER 2: Andrew is 15 years old.
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CHECK:
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A+B=28yrs
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15yrs+13yrs=28yrs
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28yrs=28yrs
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