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The area of master piston of a hydraulic press is 10 cm^2 and the area of the slave piston is 1000 cm^2.
When an effort of 50 n is exerted on the master piston calculate: the pressure in the hydraulic fluid, and the maximum weight the press can lift
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The pressure (in Pascals) in the hydraulic fluid is an effort (in newtons) divided by the area of master piston ():
P = = = 50000 Pa.
This pressure is exerted on the slave piston surface area too.
Hence, the maximum weight the press can lift is the product of this pressure P by the area on the slave piston in :
= = 50000*0.1 = 5000 newtons.
The general rule for a hydraulic press : the forces are proportional to areas: = , or =
Each side of the last proportion is the pressure of hydraulic liquid.
On hydrailc press see this article in Wikipedia.