SOLUTION: Michelle and David's ages are consecutive integers.The sum of twice David's age and 3 less than Michelle's ages is 44. How old are Michelle and David?

Question 1012977: Michelle and David's ages are consecutive integers.The sum of twice David's age and 3 less than Michelle's ages is 44. How old are Michelle and David?
Answer by macston(5194) (Show Source): You can put this solution on YOUR website!
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M=Michelle's age; D=David's age
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D=M+1
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2D+(M-3)=44
2(M+1)+M-3=44
2M+2+M-3=44
3M-1=44
3M=45
M=15
ANSWER 1: Michelle is 15.
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D=M+1=15+1=16
ANSWER 2: David is 16.
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The results if Michelle is older are not integers.
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CHECK:
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2D+(M-3)=44
2(16)+(15-3)=44
32+12=44
44=44
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