SOLUTION: Five years from now, a father's age will be three times his son's age, and 5 years ago, he was seven times as old as his son was. What are their present ages?
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Question 1002726: Five years from now, a father's age will be three times his son's age, and 5 years ago, he was seven times as old as his son was. What are their present ages?
Answer by fractalier(6550) (Show Source): You can put this solution on YOUR website!
Call the father's and son's ages NOW, f and s.
f + 5 = 3(s + 5) = 3s + 15
f - 5 = 7(s - 5) = 7s - 35
Subtract equations and get
10 = -4s + 50
-40 = -4s
s = 10
f = 40
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