SOLUTION: 5 years ago, a mother was 7times old as her daughter.5 years hence,she will be 3times old as her daughter. find their present ages.
Algebra.Com
Question 1001163: 5 years ago, a mother was 7times old as her daughter.5 years hence,she will be 3times old as her daughter. find their present ages.
Answer by fractalier(6550) (Show Source): You can put this solution on YOUR website!
Call mom's age now, m.
Call the daughter's age now, d.
Then, five years ago,
m-5=7(d-5)=7d-35 or
m = 7d - 30
and five years hence,
m+5=3(d+5)=3d+15 or
m = 3d + 10
We can set them equal, since the m's are the same...so
7d - 30 = 3d + 10
4d = 40
d = 10
m = 40
RELATED QUESTIONS
5 years ago a mother was 7 times as old as her daughter. 5 years hence she will be 3... (answered by fractalier)
"5 years ago mother was 7 times as old as her daughter. 5 years hence she will be 3 times (answered by Aswathy)
A mother is twice as old as her daughter now, but 10 years ago, she was 3 times as
old... (answered by mananth)
A mother is 3 times as old as her daughter. Seven years ago, she was 5 times as old. How... (answered by mathsmiles)
A year ago a mother was four times as old as her daughter. Three years ago she was five... (answered by ankor@dixie-net.com)
A mother is twice as old
as her daughter now, but ten
years ago, she was 3 times as old
(answered by Theo)
a daughter is 5 years old and her mother 25 years old now.in how many years time will the (answered by stanbon)
1) A mother is five times as old as her daughter. If the sum of their ages 6 years ago... (answered by addingup)
A mother is now four times as old as her daughter, three years ago, she was five times as (answered by Timnewman)