Questions on Word Problems: Age answered by real tutors!

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Tutors Answer Your Questions about Age Word Problems (FREE)


Question 283256: A mother is twice as old as her daughter now, but 10 years ago, she was 3 times as
old as her daughter. Find their ages at present.

Answer by mananth(581) About Me  (Show Source):
You can put this solution on YOUR website!
Let the daughter's age be x
mother's age will be 2x
Ten years ago
daughter's age x-10
Mother's age 3(x-10)
x-10 =3(x=10)
x=10=3x-30
3x-x=10+30
2x=40
x=40/2
x=20 Daughter's age now
Mother's age is 2x = 2*20 = 40 years


Question 283346: HI HERES MY PROBLEM
My husband Is 4 times older than my daughter now. it 20 years he'll be twice as old.
how old is the father?

Answer by Theo(1348) About Me  (Show Source):
You can put this solution on YOUR website!
h = husband's age
d = daughter's age.

Your husband is 4 times your daughter's age now>

This is represented by the formula:

h = 4d

Your husband will be 2 times as old as your daughter in 20 years.

This is represented by the formula:

(h+20) = 2(d+20)

Since h = 4d from the first equation, then substitute 4d for h in the second equation to get:

(4d + 20) = 2(d+20)

you now have one equation in one unknown that you can solve.

simplify to get:

4d + 20 = 2d + 40

subtract 2d from both sides of the equation and subtract 20 from both sides of this equation to get:

2d = 20

divide both sides of the equation by 2 to get:

d = 10

Your daughter is 10 years old now.

Since h = 4d, then your husband is 40 years old now.

In 20 years your daughter will be 30

In 20 years your husband will be 60.

In 20 years your husband will be twice your daughter's age.

Your answer is that the father is 40 years old now.









Question 282761: Adam is 6 years older but twice Joe's age. Their total age is 27.
What are Adam and Joe's ages?

Answer by richwmiller(3894) About Me  (Show Source):
You can put this solution on YOUR website!
a=6+2j
a+j=27
a=27-j
6+2j=27-j
3j=21
j=7
a=20
check
6+2*7=20
ok


Question 282794: If Bill is 5 years older than his sister Pam, and their age totals 14 then how old is Pam?
Answer by Greenfinch(325) About Me  (Show Source):
You can put this solution on YOUR website!
Pam is X years old, Bill is X + 5 years old
2X + 5 = 14
2X = 9
X = 4.5
Pam is 4.5, Bill is 9.5 Total is 14
Are you sure you have the question written properly?


Question 282528: Joe is twice as old as sam. sam is 3 times as old as paul.The sum of all the ages is 90 years. how old is sam?
Answer by dabanfield(606) About Me  (Show Source):
You can put this solution on YOUR website!
Joe is twice as old as sam. sam is 3 times as old as paul.The sum of all the ages is 90 years. how old is sam?
Let x be Paul's age. Then Sam's age is 3*x and Joe is 2*(3*x).
The sum of their ages then is:
x + 3x + 2*(3*x) = 90
10x = 90
x = 9
Paul is 9 years old. Calculate Joe's and Sam's ages based on x=9.


Question 281526: each of the sides of an isosceles triangle is three times as long as the third side. If the perimeter of the triangle is 28cm find the length of each side of the triangle
Answer by JBarnum(408) About Me  (Show Source):
You can put this solution on YOUR website!
p=Aside+Bside+Cside
a+b+c=28
a=3c
b=3c
so 3c+3c+c=28
7c=28
c=4cm
a=12cm
b=12cm


Question 281515: a man is 5times as old as his son. In 5 years he will be only 3 times as old as his son, find the present age?
Found 2 solutions by JBarnum, Mathematicians:
Answer by JBarnum(408) About Me  (Show Source):
You can put this solution on YOUR website!
m=mans present age
s=sons present age
m=5s"a man is 5times as old as his son."
m%2B5=3%28s%2B5%29"In 5 years he will be only 3 times as old as his son" "In 5 years" means man+5 years and son+5 years
use substitution for m and solve for s
5s%2B5=3%28s%2B5%29
5s%2B5=3s%2B15%29
2s%2B5=15%29
2s=10%29
highlight%28s=5%29%29
m=5s
m=5%285%29
highlight%28m=25%29

Answer by Mathematicians(79) About Me  (Show Source):
You can put this solution on YOUR website!
These word problems are always tricky, basically you want to set up two equations in order to find both their ages.
From the first sentence, "a man is 5 times as old as his son"
I will let X be the age of the old guy and Y be the age of his son:
X+=+5Y
You can test that this equation is right, if his son was 1 years old, then the man would be 5 which is 5 times more then 1!
Continuing on with the second sentence
In 5 years he will be only 3 times as old as his son, find the present age?
If 5 years progress, both him and his son will have to add 5 years so:
X+%2B+5+=+3%28Y+%2B+5%29
To solve this equation, we know that X+=+5Y so we plug in 5Y for every X.
X+%2B+5+=+3%28Y+%2B+5%29 becomes
5Y+%2B+5+=+3%28Y+%2B+5%29 Using distribution
5Y+%2B+5+=+3Y+%2B+15 Subtract 3Y on both sides and 5 on both sides
2Y++=+10 Finally divide both sides by 2
Y+=+5
Which says his son is 5 years old, how old is the man?
Go back to any equation, this will be easiest with this one:
X+=+5Y
X+=+5%2A5
X+=+25
The man is 25 and his son is 5.


Question 281442: A couple has nine daughters. The sum of the daughters' ages is 207. The age difference between consecutive daughters is always three years. The age of the middle daughter is:
(A)21 (B) 23 (C) 25 (D) 27 (E) 29

Answer by edjones(4080) About Me  (Show Source):

Question 281087: Gina is 9 years younger than her sister, Bridgette. Two years ago, Bridgette was twice as old as Gina was. How old is Gina now?
Answer by checkley77(9423) About Me  (Show Source):
You can put this solution on YOUR website!
GINA NOW=X
BRIDGETTE=X+9
GINA 2 YEARS AGO=X-2
BRIDGETTE 2 YEARS AGO=(X+9-2)
(X+9-2)=2(X-2)
X+7=2X-4
X-2X=-4-7
-X=-11
X=11 ANS. FOR GINA'S AGE NOW.
11+9=20 ANS. FOR BRIDGETTE'S AGE NOW.
PROOF:
20-2=2(11-2)
18=2*9
18=18


Question 280956: Mothers age was twice the the age of son two years ago.after how many years will she be three times her sons age?
Answer by stanbon(29603) About Me  (Show Source):
You can put this solution on YOUR website!
Mothers age was twice the the age of son two years ago.after how many years will she be three times her sons
------
Equations:
m = 2(s-2)
(m-x) = 3(s+x)
----------------------
Two equations; three variables?
Need more information.
Cheers,
stan H.


Question 280886: ALEX IS 16 YEARS OLD AND HIS SISTER RAMIE IS 5 YEARS OLD. IN HOW MANY YEARS WILL ALEX BE EXACTLY TWICE AS OLD AS RAMIE?
Answer by richwmiller(3894) About Me  (Show Source):
You can put this solution on YOUR website!
Stop shouting. Very annoying!


Question 280621: John is twice as old as his sister Mary. Mary's age is 1/6 the age of her mother. Their mother is 30. How old are John and Mary?
Answer by richwmiller(3894) About Me  (Show Source):
You can put this solution on YOUR website!
j=2s
s=m/6
m=30
s=30/6=5
j=2*5=10


Question 280612: X is 1/2 as old as Y. Z is 2 times as old as Y. Z is how many times as old as X?
Answer by oberobic(511) About Me  (Show Source):
You can put this solution on YOUR website!
X = 1/2Y
Z = 2Y
.
redefine the equations in terms of Y = ??
.
X = 1/2Y
multiply by 2
2X = Y
Y = 2X
.
Z = 2Y
divide by 2
Z/2 = Y
Y = Z/2
.
Since they both = Y, we can put them = to one another.
therefore,
2X = Z/2
multiply by 2
4X = Z
.
so we can say Z is 4 times as old as X.
.
done


Question 280536: josh is x years old now.Represent his age 10 years from now.

Answer by Theo(1348) About Me  (Show Source):
You can put this solution on YOUR website!
Josh's age 10 years from now will be represented by x + 10 if Josh's age today is represented by x.



Question 280191: poppy ans sesame bagels are bought to a brunch in a ratio of 3 poppy bagels to one sesame bagel. if there are 100 bagels in total, how many poppy bagels are there
Answer by rfer(3384) About Me  (Show Source):

Question 280026: Not wanting to be embarrassed by revealing her age on her birthday, Grandma instead told the grandkids that if they multiplied her age in 5 years by 5, then multiplied her age in 6 years by 6, and added the two totals together, they would get a number that is 12 times her current age. When she saw the large wax forest fire atop her birthday cake , Grandma knew they had figured it out. How old is she?
Answer by mananth(581) About Me  (Show Source):
You can put this solution on YOUR website!
Not wanting to be embarrassed by revealing her age on her birthday, Grandma instead told the grandkids that if they multiplied her age in 5 years by 5, then multiplied her age in 6 years by 6, and added the two totals together, they would get a number that is 12 times her current age. When she saw the large wax forest fire atop her birthday cake , Grandma knew they had figured it out. How old is she?
let her age be x now
after 5 years
(x+5)*5
after 6 years
(x+6)*6

5(x+5) +6(x+6) = 12x
5x+25+6x+36=12x
11x+61=12x
12x-11x=61
x=61



Question 279943: jon is 13 years older than tony. the sum of their ages is 27. how old are they?
Answer by richwmiller(3894) About Me  (Show Source):
You can put this solution on YOUR website!
a sneaky way
27-13=14
14/2=7
7+13=20
20+7=27
7 and 20 are the ages
Why does this work?
another way.
j=t+13
j+t=27
j-t=13
add
2j=40
j=20
27-20=7=t


Question 279667: in 13 years i will be twice as old as i was 7 years ago. what is my age

Answer by mananth(581) About Me  (Show Source):
You can put this solution on YOUR website!
Let my age be x
x+13 = 2(x-7)
x+13= 2x-14
x=27 the present age


Question 279612: The difference of two numbers is 20 and their product is -96. How do I find their numbers??
Answer by unlockmath(449) About Me  (Show Source):
You can put this solution on YOUR website!
Hello,
We can set up two equations and solve it from there. We'll let x be one number and y be the other.
x-y=20
x(y)=-96
Let's put the second equation to look like this:
x=-96/y
Now we can plug this into the first to get:
-96/y-y=20 Multiply this by y to get
-96-y^2=20y Get this with everything on one side of the = sign.
0=y^2+20y+96 Factor this to get:
0=(y+8)(y+12)
y=-8
y=-12
Plugging these numbers into the equations give us:
x=12
x=8
There we go.
RJ
www.math-unlock.com


Question 279555: ANNES AGE IS SEVEN-TENTHS OF BILLS AGE.IN 4 YEARS ANNES AGE WILL BE EIGHT-ELEVENTHS OF BILLS AGE.HOW OLD IS BILL NOW?
Answer by richwmiller(3894) About Me  (Show Source):
You can put this solution on YOUR website!
Stop shouting!
All caps is shouting!
a=7/10*b
a+4=8/11(b+4)
a=28
bill =40 years
check
28=7/10*40
28=28
32=8/11(44)
32=32
ok


Question 279375: I was five times as old as my sister five years ago, and I am three times older than her now. How old am I?
Answer by scott8148(3755) About Me  (Show Source):
You can put this solution on YOUR website!
then ___ x - 5 = 5 (s - 5) ___ x = 5s - 20

now ___ x = 3s

substituting ___ 3s = 5s - 20 ___ s = 10

substituting ___ x = 3(10) = 30


Question 279273: joe's age is 4 less than the age of his brother tom. the sum of their age is 41. find the age of each.
Answer by Grinnell(28) About Me  (Show Source):
You can put this solution on YOUR website!
Let x be Joe's age.
Let x+4 be Tom's age.
x+x+4=41
2x=37
x=18.5
Joe's age is 18.5 Years Old.
Tom's age is 22.5 Years Old.
This an elementary algebra substitution
problem. Go over this problem and many like these. Have a great afternoon!!!!!


Question 279065: Anita has two sisters and three brothers. The mean of all their ages is 6 years. What will their mean age be 10 years from now? Twenty years from now?
Found 2 solutions by Mr.Gardner, oberobic:
Answer by Mr.Gardner(4) About Me  (Show Source):
You can put this solution on YOUR website!
This is how I answered the question. If you let the siblings be represented by the letters a,b,c,d,e,f (there are six of them including Anita), then you can set up the following equation:
(a+b+c+d+e+f)/6 = 6.
This comes from the formula for a mean.
In ten years, each sibling will have added 10 years to their age, so this is the equation for the mean of their ages ten years from now:
[(a+10)+(b+10)+(c+10)+(d+10)+(e+10)+(f+10)]/6
By adding all of the 10's in the numerator we get:
(60+a+b+c+d+e+f)/6
We can seperate this fraction into:
60/6 + (a+b+c+d+e+f)/6
60/6 = 10 and we know that (a+b+c+d+e+f)/6 = 6, so the answer is:
10+6 = 16.
So in ten years the mean age increased 10 years.
Using the same arithmetic we get that the mean age in 20 years will have increased 20 years, so the answer to the second question is 26.

Answer by oberobic(511) About Me  (Show Source):
You can put this solution on YOUR website!
mean = sum / count
mean = 6
count = 6
x = sum
6 = x / 6
x = 36
.
In 10 years, the sum will be x+10 = 36 + 10 = 46
mean = 46 / 6 = 7 2/3 = 7.67
.
Done


Question 278836: Paul's father is 2 years older than his mother. Paul's age is one third his father's age. When Paul was born, the sum of his parent's age was 42. How old are Paul's parents now?
Answer by ankor@dixie-net.com(7696) About Me  (Show Source):
You can put this solution on YOUR website!
Paul's father is 2 years older than his mother.
Paul's age is one third his father's age.
When Paul was born, the sum of his parent's age was 42.
How old are Paul's parents now?
:
Let f = father's present age
Let m = mother's present age
Let p = paul's present age
:
"Paul's father is 2 years older than his mother."
f = m - 2
or
m = f + 2
:
"Paul's age is one third his father's age."
p = 1%2F3f
:
" When Paul was born, the sum of his parent's age was 42."
(f-p) + (m-p) = 42
:
In the above equation, replace p with 1%2F3f and m with (f+2)
(f - 1%2F3f) + (f+2) - (1%2F3f) = 42
:
2%2F3f + f + 2 - 1%2F3f = 42
;
2%2F3f + f - 1%2F3f = 42 - 2
:
2%2F3f + f - 1%2F3f = 40
:
2%2F3f + 2%2F3f = 40
multiply by 3:
2f + 2f = 3(40)
4f = 120
f = 120%2F4
f = 30 yrs
and
m = 32
:
Father is 30, mother is 32
;
:
Check solution by finding P's age
1%2F3(30) = 10 yrs is Paul,s age
:
Check solution in the statement:
"" When Paul was born, the sum of his parent's age was 42."
(30-10) + (32-10) = 42


Question 278689: How old are each of the kids with 1 being the oldest and the twins younger the sum of the ages is 17 product is a square #?
Answer by solver91311(6137) About Me  (Show Source):
You can put this solution on YOUR website!


There are only 5 possibilities given that the twins are the same age, the other child being the oldest, and the sum of their ages is 17:

not a perfect square

not a perfect square

not a perfect square

The answer

not a perfect square

John



Question 278577: Molly's age is twice Anitas. If the sum of the squares of thier ages is 80, then what are their ages?
Answer by ankor@dixie-net.com(7696) About Me  (Show Source):
You can put this solution on YOUR website!
Molly's age is twice Anitas.
If the sum of the squares of their ages is 80, then what are their ages?
:
m = 2a
:
m^2 + a^2 = 80
:
Replace m with 2a
(2a)^2 + a^2 = 80
:
4a^2 + a^2 = 80
:
5a^2 = 80
:
a^2 = 80%2F5
a^2 = 16
a = 4
then
m = 8
:
:
Check 4^2 + 8^2 = 80


Question 278544: Mary is 24 years older than her son John. The sum of their ages is 40. How old is John?

Found 2 solutions by Alan3354, rfer:
Answer by Alan3354(8321) About Me  (Show Source):
You can put this solution on YOUR website!
Mary is 24 years older than her son John. The sum of their ages is 40. How old is John?
--------------------
M = J + 24
M + J = 40
--------------
Sub for M in 2nd equ
(J+24) + J = 40
2J + 24 = 40
2J = 16
J = 8

Answer by rfer(3384) About Me  (Show Source):

Question 278524: the sum of the ages of jasmine and her mother is 100. thir years ago jasmine's mother was 9 times as old as jasmine was then. how old is jamine now?
Answer by solver91311(6137) About Me  (Show Source):
You can put this solution on YOUR website!


Let represent the mother's age now. Let represent Jasmine's age now. Thirty years ago (I'm assuming the "thir" you typed means thirty), the mother was and Jasmine was . And we are given that:



and



Re-write the second equation:



Add the re-written second equation to the first equation:





Solve for to find Jasmine's age now. To check your work, subtract that result from 100 to find the mother's age now. Then subtract 30 from each of the 'now' ages and verify that the larger is 9 times the smaller.

John



Question 278519: the sum of the ages of mike and dan is 20 years. in 4 years, dan's age will be three-fourths of mike's age. how old is mike now?

Answer by Anthea Lawn(16) About Me  (Show Source):
You can put this solution on YOUR website!
let m = mikes age, d = dans age.
from the first statement : m+d = 20 so d = 20-m
from the second statement (3/4)(m+4) = d+4
working a bit on the second statement gives :
3(m+4) = 4(d+4)
3m + 12 = 4d + 16
3m = 4d + 4
substituting from the first statement :
3m = 4(20-m) + 4
3m = 80 - 4m + 4
7m = 84
m = 12
So Mike is 12 and Dan is 8


Question 278434: Raul is 5 years older than twice Carlos' age. the sum of their ages is 101 how old is Carlos ?

Answer by richwmiller(3894) About Me  (Show Source):
You can put this solution on YOUR website!
r=5+2c
r+c=101
r=101-c
5+2c=101-c
3c=96
carlos =32
64+5=r
r=69
check
r+c=32+69=101
ok


Question 278390: hello, i need help on solving this type of word problem, but im not sure on how to solve it the problem is Mr.Klinker is 35 and his daughter is 10. In how many years will Mr. Klinker be twice as old as his daughter? Could you please help? thank you.
Found 2 solutions by Alan3354, stanbon:
Answer by Alan3354(8321) About Me  (Show Source):
You can put this solution on YOUR website!
The age difference is 25, so the daughter will be 25 and he will be 50.
Can you take it from there?

Answer by stanbon(29603) About Me  (Show Source):
You can put this solution on YOUR website!
Mr.Klinker is 35 and his daughter is 10.
In how many years will Mr. Klinker be twice as old as his daughter?
-------------------
Let the number of years be "x".
Equation:
(35+x) = 2(10+x)
35 + x = 20 + 2x
x = 35-20
x = 15 (K will be twice as old as his daughter in 15 years)
====================================
Cheers,
Stan H.


Question 278342: Sum of present ages of a man and his son is 60 years. Five years ago the mans age was 4 times his sons age. Then find their present ages.
Answer by mananth(581) About Me  (Show Source):
You can put this solution on YOUR website!
Sum of present ages of a man and his son is 60 years. Five years ago the mans age was 4 times his sons age. Then find their present ages.
Let the son's age be x
Father's age will be 60-x
5 years ago
(60-x) -5 = (x-5) *4
300-5x -5= 4x-20
300+20-5=4x+5x
315= 9x
x=25 years
FAther's age = 60-25 = 35.





Question 278344: Cary is 9 yrs. old than Dan. In 7 years their ages 93. Find the ages of each man now.
Answer by mananth(581) About Me  (Show Source):
You can put this solution on YOUR website!
Cary is 9 yrs. old than Dan. In 7 years their ages 93. Find the ages of each man now.
Let Dan's age be x now
Cary's age now will be x+9
after 7 years
(x+7) + (x+9+7) =93
2x+23=93
2x=93-23
2x=70
x=35 which is Dan's age.
Cary will be 35+9 = 44 years.


Question 278214: four years ago, marion was 2/3 as old as les was.now she is 3/4 as old as he is. how old is each now?
I know that i have to always compare the ages in the same time, so i have
2/3m=L
3/4m plus 4=L plus 4
I am fairly certain the second equation is wrong.

Answer by scott8148(3755) About Me  (Show Source):
You can put this solution on YOUR website!
M = "Marion NOW" ___ L = "Les NOW"

"four years ago, marion was 2/3 as old as les was" ___ M - 4 = 2/3 (L - 4)

"now she is 3/4 as old as he is" ___ M = (3/4) L

substituting ___ (3/4)L - 4 = 2/3 (L - 4)

9 L - 48 = 8L - 32 ___ L = 16

substituting ___ M = (3/4)(16) = 12


Question 278015: 5. The ages of Peter, Margaret and Jack are consecutive odd numbers. The sum of the ages of Peter and Margaret equals Jack’s age before 5 years. Find the ages of Peter, Margret and jack
Answer by richwmiller(3894) About Me  (Show Source):
You can put this solution on YOUR website!
Sorry but this is not English.
"The sum of the ages of Peter and Margaret equals Jack’s age before 5 years."


Question 277803: Sammy takes 5 hours longer to complet 300 lines of code than Martin. Together Sammy and Martin can complete the code in 6 hours.
How long it takes each programmer to complete the code if they program on their own. (hint: Quadratic equaiton )and 2) at what speed they are programming lines per hour.

Answer by checkley77(9423) About Me  (Show Source):
You can put this solution on YOUR website!
1/X+1/(X+5)=1/6
(X+5+X)/X(X+5)=1/6
(2X+5)/(X^2+5X)=1/6 CROSS MULTIPLY
X^2+5X=6(2X+5)
X^2+5X=12X+30
X^2+5X-12X-30=0
X^2-7X-30=0
(X-10)(X+3)=0
X-10=0
X=10 HOURS FOR MARTIN CODING ALONE.
10+5=15 HOURS FOR SAMMY CODING ALONE.
Proof:
1/10+1/15=1/6
(15+10)/150=1/6
25/150=1/6
1/6=1/6
300/10=30 LINES OF CODE PER HOUR FOR MARTIN.
300/15=20 LINES OF CODE PER HOUR FOR SAMMY.


Question 277454: the sum of the first six terms of a geometric progression is nine time the sum of the first three terms, where neither the first nor the common ratio is equal to zero. find the common ratio.
Answer by Edwin McCravy(3634) About Me  (Show Source):
You can put this solution on YOUR website!
the sum of the first six terms of a geometric progression is nine time the sum of the first three terms, where neither the first nor the common ratio is equal to zero. find the common ratio.


Let the first term be a and the common ratio be r

Sum of first three terms = a%2Bar%2Bar%5E2

Let this sum of the first three terms be X

Sum of first six terms = a%2Bar%2Bar%5E2%2Bar%5E3%2Bar%5E4%2Bar%5E5

Sum of first six terms = X%2Bar%5E3%2Bar%5E4%2Bar%5E5=X%2Br%5E3%28a%2Bar%2Bar%5E2%29=X%2Br%5E3X

We are given that X%2Br%5E3X=9X.  Divide through by X and we have

1%2Br%5E3=9

r%5E3=8

r=root%283%2C8%29

r=2

Check: Suppose the first term is a. Then the first six terms are

a,2a,4a,8a,16a,32a

The sum of the first three terms is a+2a+4a = 7a

The sum of the first 6 terms is a+2a+4a+8a+16a+32a=63a which is 9 times 7a.

So the answer is r=2.

Edwin


Question 277047: a man was 32 years old when his daughter was born. he is now five times older than his daughter. how old is his daughter now?
Answer by ankor@dixie-net.com(7696) About Me  (Show Source):
You can put this solution on YOUR website!
man was 32 years old when his daughter was born.
m = (d + 32)
:
he is now five times older than his daughter.
m = 5d
;
how old is his daughter now?
:
Replace m with (d+32)
d + 32 = 5d
32 = 5d - d
32 = 4d
d = 8 yrs old is daughter now
:
:
Check solution
The man = 5(8) = 40 yrs old
"he is now five times older than his daughter."
40 = 5(8)


Question 277200: tom is now 4 times as old as todd.in three years tom's age will be 13 years more than 2 times as old as tom. how old is tom?
Answer by JBarnum(408) About Me  (Show Source):
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T=tom D=todd
T=4D "tom is now 4 times as old as todd"
T%2B3=13%2B2%28D%2B3%29 "in three years tom's age will be 13 years more than 2 times as old as tom" Remember to add 3 years to both T and D
use substitution to solve for D
T%2B3=13%2B2%28D%2B3%29 T=4D
%284D%29%2B3=13%2B2%28D%2B3%29 Use order of opperations
%284D%29%2B3=13%2B%282D%2B6%29 add
%284D%29%2B3=19%2B2D subtract
%282D%29=16 divide
D=8
T=4D substitute
T=4%288%29 multiply
highlight+%28T=32%29


Question 276847: the sum of the ages of three children is 32 the age of the oldest is twice the age of the youngest the ages of the two oldest differ between 3 years what are the ages of the three children?
Answer by mananth(581) About Me  (Show Source):
You can put this solution on YOUR website!
the sum of the ages of three children is 32 the age of the oldest is twice the age of the youngest the ages of the two oldest differ between 3 years what are the ages of the three children?
let the youngest be x
The oldest will be 2x
The other child's age will be 32- (2x+x)
2x - (32-3x)=3
2x-32 +3x=3
5x=35
x= 7 the youngest
the oldest will be 14 years
The third child will be 11 years



Question 276487: Hannah, Mark and Tom have a combined age of 68. Hannah is twice as old as the di erence between Mark and Tom's age. Mark and Tom's combined age is 16 times
Hannah's age. Mark is older than Tom. How old is Tom?
(a) 31 (b) 32 (c) 33 (d) 34 (e) None of the above

Answer by ankor@dixie-net.com(7696) About Me  (Show Source):
You can put this solution on YOUR website!
Hannah, Mark and Tom have a combined age of 68.
h + m + t = 68
:
Hannah is twice as old as the di fference between Mark and Tom's age.
h = 2(m - t)
:
Mark and Tom's combined age is 16 times Hannah's age.
m + t = 16h
-16h + m + t = 0
:
Subtract the above equation from the 1st equation
h + m + t = 68
-16h + m + t = 0
-------------------subtraction eliminates m & t, find h
17h = 68
h = 68%2F17
h = 4 yrs is Hannah's age
:
Replace h with 4 in the equation m + t = 16h
m + t = 16(4)
m + t = 64
:
Replace h in the equation h = 2(m-t)
2(m - t) = 4
Simplify, divide by 2
m - t = 2
;
Add the two equation
m + t = 64
m - t = 2
-------------
2m = 66
m = 33 yrs is Marks age
then
31 is Tom's age
:
:
Check total
4 + 33 + 31 = 68





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