Questions on Word Problems: Age answered by real tutors!

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Tutors Answer Your Questions about Age Word Problems (FREE)


Question 752173: A doctor's age 8 years ago is two-thirds his age 13 years hance. How old is he now?
Answer by anamika1310(3) About Me  (Show Source):
You can put this solution on YOUR website!
let the doctor's age be x.
so,
x-8 = 2/3(x+13)
3x-24=2x+26
x=50
So, his present age is 50.
hope this is it.


Question 751452: Currently Doris is one year older than twice Arthurs age. In ten years time the sum of their ages will be 39. Determine their current ages now.
Answer by kmadison(2) About Me  (Show Source):
You can put this solution on YOUR website!
Equation for Arthur's age in respect to Doris: D = 2A + 1
After ten years time
(D + 10) = 2(A + 10) + 1
So we need to find D + A = 39, or (D + 10) + 2(A + 10) + 1 = 39 = 2D + A + 31 = 39
We have 2 equations, 2 unknowns so we eliminate 1 variable
We know that D = 2A + 1 Therefore 39 = D + 30 => D = 9
9 = 2A + 1 => 2A = 8 or A = 4
So now, Doris is 9, and Arthur is 4.



Question 751250: John is four years younger than clement. if their ages are in ratio of 7:9. What is the age of john
Answer by ankor@dixie-net.com(15656) About Me  (Show Source):
You can put this solution on YOUR website!
John is four years younger than clement.
if their ages are in ratio of 7:9.
What is the age of john
:
let x = the multiplier
then
7x = J's age
and
9x = C's age
:
"John is four years younger than clement."
7x = 9x - 4
4 = 9x - 7x
4 = 2x
x = 4/2
x = 2 is the multiplier
then
7(2) = 14 yrs is J's age
:
:
You can confirm this by finding C's age
9(2) = 18 is C's age, 4 yrs older than J


Question 751273: Penny bought a scarf for $5.00, spent ˝ of her remaining money on jogging shoes, bought lunch for $2.00, then spent ˝ of the remaining money on a present. She then had $10 left. How much money did she start with?
Answer by josmiceli(9686) About Me  (Show Source):
You can put this solution on YOUR website!
Let +x+ = amount of money she started with
After buying scarf for $5, she has +x+-+5+ remaining
------------------
She spent ˝ of her remaining money on jogging shoes, or
+%28+x-5+%29+%2F+2+, and she has +%28+x-5+%29%2F+2+ left.
------------------
She bought lunch for $2.00
She has +%28+x-5+%29+%2F2+-+2+ left
--------------------------
She spent ˝ of the remaining money on a present, so
she has +%28%28%28+x-5+%29+%2F2+-+2+%29%29+%2F+2+ left
---------------------
She has $10 left, so
+%28%28%28+x-5+%29+%2F2+-+2+%29%29+%2F+2+=+10+
+%28+x-5+%29+%2F2+-+2++=+20+
+%28+x-5+%29+%2F+2+=+22+
+x+-+5+=+44+
+x+=+49+
She started with $49
------------------
check:
After buying scarf for $5, she has $44 remaining
------------------
She spent ˝ of her remaining money on jogging shoes, or
$22, and she has $22 left.
----------------------
She bought lunch for $2.00
She has $20 left
--------------------------
She spent ˝ of the remaining money on a present, so
she has $10 left
OK




Question 751040: mother daughter older than 30 years.
how many will be older than his daughter for 10 years
How many times the mother will be more than daughters when the daughter is 30 years old had

Answer by dkppathak(43) About Me  (Show Source):
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mother is 30 yrs older than her daughter
after ten yrs mother will be 40 yrs and daughter will be 10 yrs
difference of age between mother and daughter will remain as 40-10 =30 yrs
when daughter is 30 yrs old
mother will be 60 yrs
therefore mother will be two times of daughter age
ANSWER two times


Question 751041: a father is 61 and his son is 16 years old.in how many years will the father be twice as old as his son?

Answer by dkppathak(43) About Me  (Show Source):
You can put this solution on YOUR website!
father is 61 yrs
and son is 16 yrs
as per conditions in how many years father will be two times son age
let x years after
father =61+x
son = 16+x
61+x= 2(16+x)
61+x =32+ 2x
2x-x=61-32 =29
yrs
answer after 29 yrs father will be twice of son age


Question 751002: Hello sir ,I am having a problem???
If the fathers age is reversed we will get sons age ??? two years ago fathers age was twice as that of sons age??What is their present ages????

Answer by MathTherapy(1425) About Me  (Show Source):
You can put this solution on YOUR website!

Hello sir ,I am having a problem???
If the fathers age is reversed we will get sons age ??? two years ago fathers age was twice as that of sons age??What is their present ages????

Your problem wasn't stated clearly.

Anyway, if it's supposed to be read as, "two years ago father's age was twice as that of the son's CURRENT age," then the father's current age is: highlight_green%2852%29, and the son's current age is: highlight_green%2825%29

You can do the check!!

Send comments and “thank-yous” to “D” at MathMadEzy@aol.com


Question 750687: At present, Gilbert's age is 30% of his father's age. Thirty years from now, Gilbert's age will be 60% of his father's age. How old is Gilbert now?
Answer by ankor@dixie-net.com(15656) About Me  (Show Source):
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At present, Gilbert's age is 30% of his father's age.
g = .3f (using the decimal equiv of percent)
:
Thirty years from now, Gilbert's age will be 60% of his father's age.
g + 30 = .6(f+30)
g + 30 = .6f + 18
g = .6f = 18 - 30
g = .6f - 12
Replace g with .3f
.3f = .6f - 12
12 = .6f - .3f
12 = .3f
f = 12/.3
f = 40 yrs is Dad's age
How old is Gilbert now?
g = .3(40)
g = 12 yrs
:
:
Check this
12 + 30 = .6(40+30)
42 = .6(70)


Question 750847: Ross is five years older than twice his sister Holly's age. The difference in their ages is 14 years. How old is Holly?

I just need help setting the problem up; I can figure out the answer myself, but knowing how to set it up would be crucial.

Found 2 solutions by josgarithmetic, ankor@dixie-net.com:
Answer by josgarithmetic(1530) About Me  (Show Source):
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r for Ross age, and h for Holly age.
r=5%2B2%2Ah, Ross is five years older than twice his sister Holly's age.
r-h=14, The difference in their ages is 14 years.

I would take r from the first equation and substitute into the second equation, and solve for h. You could then use what you found for h to find value of r.

%28r%29-h=14
%285%2B2h%29-h=14
and continue...

Answer by ankor@dixie-net.com(15656) About Me  (Show Source):
You can put this solution on YOUR website!
Ross is five years older than twice his sister Holly's age.
r = 2h + 5
:
The difference in their ages is 14 years.
r - h = 14
r = (h+14); you can use this form for substitution

How old is Holly?


Question 750684: A person is 50 years old. His son is 24 years old. How many years ago was the father three times as old as his son?
Answer by ankor@dixie-net.com(15656) About Me  (Show Source):
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A person is 50 years old.
His son is 24 years old.
How many years ago was the father three times as old as his son?
:
let y = no. of years ago for this to be true\
50-y = 3(24-y)
Solve for y


Question 750776: If a group of 6 people have an average age of 21, and each person is half the age of the next person, what are the ages of the 6 people
Answer by timvanswearingen(106) About Me  (Show Source):
You can put this solution on YOUR website!
Let x be the age of the youngest of the 6 people. Then the rest of their ages are 2x, 4x, 8x, 16x, and 32x.
Since their average age is 21, 21*6=126. The sum of their ages is 126.
x%2B2x%2B4x%2B8x%2B16x%2B32x=126
63x=126
Divide both sides by 63:
x=2
So their ages are 2, 4, 8, 16, 32, and 64


Question 750646: When Matthew is 12 years old his mother is 3 times as old. How many years must pass before his mother is twice as old? How many years ago was she 7 times as old?
Answer by ankor@dixie-net.com(15656) About Me  (Show Source):
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When Matthew is 12 years old his mother is 3 times as old.
Matt = 12, Mother = 36
:
How many years must pass before his mother is twice as old?
let y = no. of years for this to be true
y + 36 = 2(y+12)
y + 36 = 2y + 24
36 - 24 = 2y - y
12 = y
This will be true in 12 yrs (Mom will be 48, Matt will be 24)
:
How many years ago was she 7 times as old?
let z = no. of yrs for this to be true
36-z = 7(12-z)
36 - z = 84 - 7z
-z + 7z = 84 - 36
6z = 48
z = 8 yrs for this to be true. (Mom will be 28, Matt will be 4)


Question 750489: Hi, I need help on how to set this problem up to get the answer
Two times Antonio’s age plus three times Sarah’s age equals 34. Sarah’s age is five times the age of Antonio. How old is Sarah?
Thanks

Answer by Alan3354(30993) About Me  (Show Source):
You can put this solution on YOUR website!
Hi, I need help on how to set this problem up to get the answer
Two times Antonio’s age plus three times Sarah’s age equals 34. Sarah’s age is five times the age of Antonio. How old is Sarah?
---------------------
Write what it says.
Two times Antonio’s age plus three times Sarah’s age equals 34.
2A + 3S = 34
------
Sarah’s age is five times the age of Antonio.
S = 5A
=================
Was that hard?


Question 750308: a 32cm long wire is bent to form a squre .what is the length of each side oh the squre?
Answer by dkppathak(43) About Me  (Show Source):
You can put this solution on YOUR website!
PERIMETER OF SQUARE IS 4X
4X=32
X=32/4 = 8CM
AREA OF SQUARE =8X8=64 SQUARE CM


Question 750305: hassan and asghar had 80 marbles.hassan had four times as many as asghar had.how many marbles did each of hassan and asghar have?
Answer by dkppathak(43) About Me  (Show Source):
You can put this solution on YOUR website!
LET HASSAN HAVE MARBELS x
ASGHAR HAVE MARBELS Y
AS PER CONDITION GIVEN
X=4Y i
AND
X+Y =80 ii
PUTTING VALUE OF EQN i IN EQN ii
4Y+Y=80
5Y=80
Y=80/5=16
HASSAN HAVE 16X4 =64
ASGHAR HAVE =16


Question 750068: A 41-year old mother has 5 children. Her youngest children are twins. If the ages of her children are consecutive integers with a sum equal to that of her age, how old are the twins?
Here are the choices:
A. 6 B. 7 C. 8 D. 9

Answer by JoeTaxpayer(135) About Me  (Show Source):
You can put this solution on YOUR website!
The twins are x.
2x+(x+1)+(x+2)+(x+3)=41
5x+6=41
5x=35
The twins are 7


Question 750042: total age of 3persons is 80years, what was the total of their age 3 years ago
Answer by tommyt3rd(606) About Me  (Show Source):
You can put this solution on YOUR website!
x+y+z=80 so three years ago their ages were
x-3
y-3
z-3
thus the old (pardon the pun) age was 80-9 = 71

:)


Question 749927: A man is ten times as old as his daughter. In 5years time he will be 5 times as old as his daughter. How old are each of them now?
Answer by josgarithmetic(1530) About Me  (Show Source):
You can put this solution on YOUR website!
man m
daughter d

highlight%28m=10%2Ad%29
m%2B5=5%2A%28d%2B5%29 which may be initially worked into m%2B5=5d%2B25 or highlight%28m-5d=20%29.

Solve the system of equations, each being highlighted.


Question 749934: I am 40 years old, and that means I am twice as old now as Kat was when I was as old as Kat is now. How old is kat.
Answer by josmiceli(9686) About Me  (Show Source):
You can put this solution on YOUR website!
Let +k+ = Kat's age now in years
The difference in our ages is ( and always was )
+40+-+k+
When I was as old as Kat is now, I was +k+ years old
Kat is younger by the difference in our ages, so Kat was
+k+-+%28+40+-+k+%29+=+2k+-+40+
I am twice as old as that now, so I am
+2%2A%28+2k+-+40+%29+
I am +40+ now, so
+2%2A%28+2k+-+40+%29+=+40+
+4k+-+80+=+40+
+4k+=+120+
+k+=+30+
Kat is 30
-----------
check answer:
When I was as old as Kat is now, I was +30+
That was +10+ years ago, so Kat was +20+
Am I twice that age? Yes, I am +40+
OK


Question 749797: John is 5 years older than bob. Three years ago he was twice as bob. How old is john?
Answer by ankor@dixie-net.com(15656) About Me  (Show Source):
You can put this solution on YOUR website!
John is 5 years older than bob.
j = b+5
:
Three years ago he was twice as bob.
j-3 = 2(b-3)
j - 3 = 2b - 6
j = 2b - 6 + 3
j = 2b - 3
replace j with (b+5)
b + 5 = 2b - 3
5 + 3 = 2b - b
b = 8 yr is Bob's age
:
How old is john?
j = 8 +5
j = 13
:
:
Check solutions in the statement:
"Three years ago he was twice as bob."
13 - 3 = 2(8-3); confirms our answer


Question 749779: The sum of the ages of two brothers is 38 years. Four years ago, the age of the elder brother was the square of the younger brother's age.Find their ages.
Found 2 solutions by ankor@dixie-net.com, stanbon:
Answer by ankor@dixie-net.com(15656) About Me  (Show Source):
Answer by stanbon(57361) About Me  (Show Source):
You can put this solution on YOUR website!
The sum of the ages of two brothers is 38 years. Four years ago, the age of the elder brother was the square of the younger brother's age.Find their ages.
------
Equations:
a + b = 38 years
a-4 = (b-4)^2
--------------------
Rearrange:
a = 38-b
Substitute for "a" and solve for "b":
(38-b)-4 = b^2 - 8b + 16
b^2 - 7b -18 = 0
----
(b-9)(b+2) = 0
----
Positive solution:
b = 9 (one of the brother's age)
Solve for "a":
a + b = 38
a + 9 = 38
a = 29 (age of the other brother)
==================
Cheers,
Stan H.
==================


Question 749305: A father is four times as old as his son and his daughter is five years younger than her brother. If their combined ages amount to 73 years, find the age of each
Answer by ankor@dixie-net.com(15656) About Me  (Show Source):
You can put this solution on YOUR website!
A father is four times as old as his son and his daughter is five years younger than her brother.
If their combined ages amount to 73 years, find the age of each
:
Let f = father's age
let s = son's age
let d = daughter's age
:
Write an equation for each statement:
:
"A father is four times as old as his son"
f = 4s
:
"his daughter is five years younger than her brother."
d = s-5
:
"their combined ages amount to 73 years,"
f + s + d = 73
replace f with 4s, replace d with (s-5)
4s + s + (s-5) = 73
6s = 73 + 5
6s = 78
s = 78/6
s = 13 yrs is son's age
:
I'll let you find f and d, check your solutions in the total age


Question 749511: a man was 32 when his son was born. Ten years ago he was three times as old as his son. Find their ages now.
Answer by Alan3354(30993) About Me  (Show Source):
You can put this solution on YOUR website!
a man was 32 when his son was born. Ten years ago he was three times as old as his son. Find their ages now.
---------------
Age difference = 32
3 times --> 48 & 16
48 + 10 = 58 & 26 now


Question 749411: Marie is 16 and twice as old as bobby. how old will Marie be when she's twice as old as bobby?
Found 2 solutions by Alan3354, lynnlo:
Answer by Alan3354(30993) About Me  (Show Source):
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Marie is 16 and twice as old as bobby. how old will Marie be when she's twice as old as bobby?
----------
She's twice as old now.
= 16

Answer by lynnlo(4164) About Me  (Show Source):
You can put this solution on YOUR website!
OK,IF MARIA IS 16,8+8=16,WHICH IS HER AGE TWICE AS BOBBY,16


Question 749368: the sum of two number is 28.if the second number is thrice the first ,what is the second number.

Answer by mykailao(6) About Me  (Show Source):
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The sum is 28.
Let x = first no.
Let 3x = second no.
x + 3x = 28
4x = 28
x = 7
Answer:
First no. = x = 7
Second no. = 3x = 21


Question 749371: naureen and farrah have a total of 300 rupees.if naureen has twice as many rupees as farah has,what is each ones share?
Answer by mykailao(6) About Me  (Show Source):
You can put this solution on YOUR website!
Sum of Naureen and Farrah's rupees = 300
Let x = no. of rupees Farrah has
Let 2x = no. of rupees Naureen has
x + 2x = 300
3x = 300
x = 100.
Answer: Farrah has 100 rupees, and Naureen has 200 rupees.


Question 749369: if the measure of one angle of a right traingle is 30,what is the measure of the other angle.
Answer by mykailao(6) About Me  (Show Source):
You can put this solution on YOUR website!
Remember that one of the angles of a right triangle is always 90 degrees.
And the sum of three angles of a triangle is always 180 degrees.
Therefore, 180 - (90+30) = 60.
Ans: The other angle is 60 degrees.


Question 749277: William is 5 years older than Roberto. Roberto is 3 years older than Ashley. If Ashley is 14 years old, how old is William?
Answer by 932982(3) About Me  (Show Source):
You can put this solution on YOUR website!
William= 5+ Robert
Robert= 3+ Ashley
Ashley= 14
Robert= 3+14(Ashley's age) = 17
William= 5+17(Robert's age) =22
William= 22 years old


Question 749104: Young's rule, C=DA/a+12, can be used to approximate the dosage of a drug prescribed for children. In this formuala, A= childs age in years, D= an adult dosage and C= the proper childs dosage. When an adult dosage is 12 milligrams and the child's dosage is 300 milligrams, what is the childs age?
Answer by josgarithmetic(1530) About Me  (Show Source):
You can put this solution on YOUR website!
Simply solve the equation for A and substitute the known values.
C-12=DA%2Fa
%28a%2FD%29%28C-12%29=A, formula for A.


Question 748520: The average age of a board of 10 advisors of a company is the same as it was 3 year back on account of the replacement of one of the older advisors by younger men.what is the difference between older and younger man?
Answer by ankor@dixie-net.com(15656) About Me  (Show Source):
You can put this solution on YOUR website!
The average age of a board of 10 advisors of a company is the same as it was 3
year back on account of the replacement of one of the older advisors by younger men.
what is the difference between older and younger man?
:
Let a = the average age
:
let y = age of the younger man
:
%28%2810a+-+30%29%29%2F10 = %28%289a%2By%29%29%2F10
multiply both sides by 10
10a - 30 = 9a + y
10a - 9a = y + 30
a = y + 30
:
30 years between older and younger man


Question 748706: My mum is 3 times as old as I am. If she is 24 years older than me, what are our ages?
Answer by stanbon(57361) About Me  (Show Source):
You can put this solution on YOUR website!
My mum is 3 times as old as I am.
If she is 24 years older than me, what are our ages?
------------
Let mum = m
Let self = s
----
Equations:
m = 3s
m = s + 24
-----
3s = s+24
2s = 24
s = 12 (Self's age now)
----
m = 3s = 36 (mum's age now)
===============================
Cheers,
Stan H.
=================


Question 748631: what expression represents the product of four more then twice xand six less then x
Answer by tommyt3rd(606) About Me  (Show Source):
You can put this solution on YOUR website!
the product of - means multiply so we look for 2 quantities typically separated by the word and
four more than twice x means 2x+4

six less than x means x-6


our product:
(2x-4)(x-6)


Question 748613: Penny is p years old. Form algebraic expressions with the variable p that represents the ages requested.
The current age of Penny's little brother, who will be half Penny's age in two more years.

Answer by tommyt3rd(606) About Me  (Show Source):
You can put this solution on YOUR website!
We add 2 to Penny's current age and divide the result by 2:

B=(P+2)/2


Question 748610: The difference between the present age of the father and son is 30. 5 years ago, the son age is one seventh of the father age. find their present age.
Answer by tommyt3rd(606) About Me  (Show Source):
You can put this solution on YOUR website!
The difference between the present age of the father and son is 30 means
F-S=30
which we rewrite as F=S+30


5 years ago, the son age is one seventh of the father age means
7(S-5)=F-5
which we rewrite as F=7S-30

Now we can write
S+30 = 7S-30
6S =60
S=10
and so F=S+30=10+30=40

Sons is 10 and father is 40



:)


Question 748481: in 10 years, frederick will be thrice as old as he was 8 years ago. How old is he know?
Answer by nilan(15) About Me  (Show Source):
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let the frederic age is x now
so 8 years ago his age was x-8
in 10 years his age will be x+10
in 10 years, frederick will be thrice as old as he was 8 years ago
which means
x%2B10+=+3%28x-8%29
x%2B10+=+3x-24
10%2B24+=+3x-x
34+=+2x
x=17
so he is 17 years old now


Question 748158: Crisner is 3 years older than her niece Josephine. In 7 years she will be six seventh of her age. How old are they?
Answer by ankor@dixie-net.com(15656) About Me  (Show Source):
You can put this solution on YOUR website!
): Crisner is 3 years older than her niece Josephine.
In 7 years she will be six seventh of her age.
How old are they?
:
Let c = C's age now
Let j = J's age
;
Write an equation for each statement
:
"): Crisner is 3 years older than her niece Josephine."
c = j + 3
:
"In 7 years she will be six seventh of her age."
j + 7 = 6%2F7(c+7)
Get rid of that annoying fraction, mult both sides by 7
7(j+7) = 6(c+7)
7j + 49 = 6c + 42
7j = 6c + 42 - 49
7j = 6c - 7
replace c with (j+3) from the 1st statement
7j = 6(j+3) - 7
7j = 6j + 18 - 7
7j - 6j = 11
j = 11 yrs is J's age
then
11 + 3 = 14 yrs is C's age
;
;
see if that works
j + 7 = 6%2F7(c+7)
11 + 7 = 6%2F7(14+7)
18 = 6%2F7(21)
7 cancels into 21
18 = 6(3)









Question 748228: shaun is 9 years older than his younger sister Mary. In 7 years time, he will be twice as old as she is. How old are they now?
Answer by lynnlo(4164) About Me  (Show Source):

Question 748241: If Adam is 15 years younger than Alicia and in 6 years Alicia will be twice as old as Adam, how old is Adam?
Answer by timvanswearingen(106) About Me  (Show Source):
You can put this solution on YOUR website!
Let x represent Alicia's age now.
Adam's age would be x-15
In 6 years, Alicia will be x+6 and Adam will be x-15+6 or x-9.
At that time, Alicia will be twice as old as Adam.
Thus, 2 times Adam's age should be equal to Alicia's age:
2%28x-9%29=x%2B6
Distribute:
2x-18=x%2B6
Subtract x from both sides:
x-18=6
Add 18 to both sides:
x=24
Adam's age was represented by x-15, so plug in 24 for x:
24-15
9
Adam is 9 years old.


Question 748146: What would be the equation for this question?
Two parents age adds up to 89 but the mom is 7 years older, what is the age of both the parents?

Answer by solver91311(16897) About Me  (Show Source):
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Let represent the Dad's age. Then the Mom's age is . Then



John

Egw to Beta kai to Sigma
My calculator said it, I believe it, that settles it
The Out Campaign: Scarlet Letter of Atheism



Question 747767: one person is 35years old and his son is 5 years old,after how many year age of father will be 2.5 times of sons age?
Answer by stanbon(57361) About Me  (Show Source):
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one person is 35years old and his son is 5 years old,after how many year age of father will be 2.5 times of sons age?
-----
Equatiion:
(35+x) = 2.5(5+x)
----
35+x = 12.5 + 2.5x
1.5x = 22.5
x = 15 years
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Cheers,
Stan H.
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Question 747708: what are three consecution whole numbers sum is 48?
Answer by josgarithmetic(1530) About Me  (Show Source):
You can put this solution on YOUR website!
n, n+1, n+2.

n+(n+1)+(n+2)=48
n+n+1+n+2=48
3n+3=48
.
n=15


Question 747716: Brandon is five years younger than his brother, the product of their ages is the same as their dad's age. If their dad is 50 this year, how old is Brandon?
Answer by lwsshak3(6513) About Me  (Show Source):
You can put this solution on YOUR website!
Brandon is five years younger than his brother, the product of their ages is the same as their dad's age. If their dad is 50 this year, how old is Brandon?
***
Let x=brother's age
x-5=Brandon's age
x(x-5)=50
x^2-5x-50=0
(x-10)(x+5)=0
x=10
x-5=5
Brandon's age=5


Older solutions: 1..45, 46..90, 91..135, 136..180, 181..225, 226..270, 271..315, 316..360, 361..405, 406..450, 451..495, 496..540, 541..585, 586..630, 631..675, 676..720, 721..765, 766..810, 811..855, 856..900, 901..945, 946..990, 991..1035, 1036..1080, 1081..1125, 1126..1170, 1171..1215, 1216..1260, 1261..1305, 1306..1350, 1351..1395, 1396..1440, 1441..1485, 1486..1530, 1531..1575, 1576..1620, 1621..1665, 1666..1710, 1711..1755, 1756..1800, 1801..1845, 1846..1890, 1891..1935, 1936..1980, 1981..2025, 2026..2070, 2071..2115, 2116..2160, 2161..2205, 2206..2250, 2251..2295, 2296..2340, 2341..2385, 2386..2430, 2431..2475, 2476..2520, 2521..2565, 2566..2610, 2611..2655, 2656..2700, 2701..2745, 2746..2790, 2791..2835, 2836..2880, 2881..2925, 2926..2970, 2971..3015, 3016..3060, 3061..3105, 3106..3150, 3151..3195, 3196..3240, 3241..3285, 3286..3330, 3331..3375, 3376..3420, 3421..3465, 3466..3510, 3511..3555, 3556..3600, 3601..3645, 3646..3690, 3691..3735, 3736..3780, 3781..3825, 3826..3870, 3871..3915, 3916..3960, 3961..4005, 4006..4050, 4051..4095, 4096..4140, 4141..4185, 4186..4230, 4231..4275, 4276..4320, 4321..4365, 4366..4410, 4411..4455, 4456..4500, 4501..4545, 4546..4590, 4591..4635, 4636..4680, 4681..4725, 4726..4770, 4771..4815, 4816..4860, 4861..4905, 4906..4950, 4951..4995, 4996..5040, 5041..5085, 5086..5130, 5131..5175, 5176..5220, 5221..5265, 5266..5310, 5311..5355, 5356..5400, 5401..5445, 5446..5490, 5491..5535, 5536..5580, 5581..5625, 5626..5670, 5671..5715, 5716..5760, 5761..5805, 5806..5850, 5851..5895, 5896..5940, 5941..5985, 5986..6030