Questions on Word Problems: Coins answered by real tutors!

Algebra ->  Algebra  -> Customizable Word Problem Solvers -> Questions on Word Problems: Coins answered by real tutors!     (Log On)
Ad: Over 600 Algebra Word Problems at edhelper.com
Ad: Algebra Solved!™: algebra software that solves YOUR algebra homework problems with step-by-step help!


Question 153636: Sandy held a garage sale during which she charged a dime for everything, but accepted a nickel if the buyer bargained well. At the end of the day she realized she had sold all 12 items and raked in a grand total of 95 cents. She had only dimes and nickels. How many of each did she have? (please show work) Thank you so much: Sandy held a garage sale during which she charged a dime for everything, but accepted a nickel if the buyer bargained well. At the end of the day she realized she had sold all 12 items and raked in a grand total of 95 cents. She had only dimes and nickels. How many of each did she have? (please show work) Thank you so much
Answer by stanbon(18984) About Me  (Show Source):
You can put this solution on YOUR website!
Sandy held a garage sale during which she charged a dime for everything, but accepted a nickel if the buyer bargained well. At the end of the day she realized she had sold all 12 items and raked in a grand total of 95 cents. She had only dimes and nickels. How many of each did she have? (please show work) Thank you so much
-------------------------------------------------
Quantity: d + n = 12
Value: 10d + 5n = 95
------------------------
Multiply the 1st equation by 10 to get:
10d + 10n = 120
10d + 5n = 95
---------------
Subtract 2nd from 1st to get:
5n = 25
n = 5 (# of nickels)
Since d+n + 12, d= 12-5; d = 7 (# of dimes)
===============================================
Cheers,
Stan H.