SOLUTION: If Steven can mix 20 drinks in 5 minutes, Sue can mix 20 drinks in 10 minutes, and Jack can mix 20 drinks in 15 minutes, how much time will it take all 3 of them working together t

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Question 149044: If Steven can mix 20 drinks in 5 minutes, Sue can mix 20 drinks in 10 minutes, and Jack can mix 20 drinks in 15 minutes, how much time will it take all 3 of them working together to mix the 20 drinks?
Found 2 solutions by ptaylor, Electrified_Levi:
Answer by ptaylor(2198) About Me  (Show Source):
You can put this solution on YOUR website!
Let x=amount of time it will it take all 3 of them working together to mix the 20 drinks. {Our final equation will be of the form: Rate at which they mix drinks when working together (drinks/min) times x minutes equals 20 drinks}
Steven mixes at the rate of 4 drinks per minute
Sue mixes at the rate of 2 drinks per minute
Jack mixes at the rate of 20/15 or 4/3=1 1/3 drinks per minute
Together, they mix at the rate of 4 + 2 + (1 1/3)=7 1/3 drinks per minute
So, our equation to solve is:
(7 1/3)*x=20 divide each side by 7 1/3
x=2.73 minutes---------------------amount of time it will it take all 3 of them working together to mix the 20 drinks
CK
2.73*7.33=20
20.019~~~~20


Hope this helps---ptaylor



Answer by Electrified_Levi(103) About Me  (Show Source):
You can put this solution on YOUR website!
Hi, Hope I can help,
.
If Steven can mix 20 drinks in 5 minutes, Sue can mix 20 drinks in 10 minutes, and Jack can mix 20 drinks in 15 minutes, how much time will it take all 3 of them working together to mix the 20 drinks?
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First, you have to make sure that all the measurements are the same(if it says Bob can do it in 5 hours, and John can do it in 45 minutes, you have to convert minutes to hours, or hours to minutes) They are all the same in our problem
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This is the way I usually solve these types of problems
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You are trying to find out how long it will take them, doing the job together.
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Here is the formula I use
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( If there was another you would add
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%28x%2F%28how+long+it+takes+for+person%284%29%29%29+, and so on)
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The "x" is how long it will take for all of them together to get the job done
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If you add the fractions together it will equal 1 job
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We can now replace the bottom numbers(denominators) with "5","10","15"( that's how long it takes each person)
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+%28x%2F5%29%2B%28x%2F10%29%2B%28x%2F15%29+=+1+
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We can now solve for "x", we will multiply everything by "30" to get rid of the denominators, and fractions
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+%2830%29%28x%2F5%29%2B%2830%29%28x%2F10%29%2B%2830%29%28x%2F15%29+=+%2830%291+
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It will become
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+6x+%2B+3x+%2B+2x+=+30+
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We will add the left side
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+11x+=+30+
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We can divide each side by "11"
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+11x%2F11+=+30%2F11+
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+x+=+30%2F11+
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If they all work together they can get the job done in 2 +8%2F11+ minutes, we can check by replacing "x" with "2 +8%2F11+" or "+30%2F11+" in our equation
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+%28%2830%2F11%29%2F5%29%2B%28%2830%2F11%29%2F10%29%2B%28%2830%2F11%29%2F15%29+=+1+
.
+%286%2F11%29%2B%283%2F11%29%2B%282%2F11%29+=+1+
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+11%2F11+=+1+
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+1+=+1+
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They can get the job done in +30%2F11+ minutes, or 2 +8%2F11+ minutes
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Hope I helped, Levi