Questions on Word Problems: Travel and Distance answered by real tutors!

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Question 148702This question is from textbook Elementary and Intermediate Algebra
: Avoiding a collision. A car is traveling on a road that is perpendicular to a railroad track. When the car is 30 meters from the crossing, the car's new collision detector warns the friver that there is a train 50 meters from the car and heading toward the same crossing. How far is the train from the crossing?This question is from textbook Elementary and Intermediate Algebra
: Avoiding a collision. A car is traveling on a road that is perpendicular to a railroad track. When the car is 30 meters from the crossing, the car's new collision detector warns the friver that there is a train 50 meters from the car and heading toward the same crossing. How far is the train from the crossing?
Answer by nerdybill(743) About Me  (Show Source):
You can put this solution on YOUR website!
Avoiding a collision. A car is traveling on a road that is perpendicular to a railroad track. When the car is 30 meters from the crossing, the car's new collision detector warns the friver that there is a train 50 meters from the car and heading toward the same crossing. How far is the train from the crossing?
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Draw a diagram of the situation and label the information provided.
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Once you do that, you should see that the "front of the car", the "center of the crossing" and the "front of the train" forms a "right triangle". Now, you can apply Pythagorean's theorem:
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Let x = distance of train from crossing
then
x^2 + 30^2 = 50^2
x^2 + 900 = 2500
x^2 = 2500 - 900
x^2 = 1600
x = 40 feet