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Question 155230This question is from textbook elementary and intermediate algebra
: Chapter. 6 Math 209
BONUS: Word Problem.Please Help
Brenda and her husband Randy bicycled cross-country together. One morning, Brenda rode 30 miles. By traveling only 5 miles per hour faster and putting in one more hour, Randy covered twice the distance Brenda covered.
What was the speed of each cyclist?This question is from textbook elementary and intermediate algebra
: Chapter. 6 Math 209
BONUS: Word Problem.Please Help
Brenda and her husband Randy bicycled cross-country together. One morning, Brenda rode 30 miles. By traveling only 5 miles per hour faster and putting in one more hour, Randy covered twice the distance Brenda covered.
What was the speed of each cyclist?
Answer by scott8148(2758) About Me  (Show Source):
You can put this solution on YOUR website!
r*t=d

Brenda __ r*t=30 __ t=30/r

Randy __ (r+5)(t+1)=60 __ substituting __ (r+5)((30/r)+1)=60 __ multiplying by r __ (r+5)(30+r)=60r

FOILing __ r^2+35r+150=60r __ subtracting 60r __ r^2-25r+150=0 __ factoring __ (r-15)(r-10)=0

r-15=0 __ r=15

r-10=0 __ r=10

there are two solutions
__ Brenda going 10 mph for 3 hr while Randy goes 15 mph for 4 hr
__ Brenda going 15 mph for 2 hr while Randy goes 20 mph for 3 hr