SOLUTION: Smith has three times as much money as Prakash.If smith gives Rs 750 to Prakash,Prakash will have twice as much as left with smith.How much each had initially?

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: Smith has three times as much money as Prakash.If smith gives Rs 750 to Prakash,Prakash will have twice as much as left with smith.How much each had initially?      Log On


   



Question 147188: Smith has three times as much money as Prakash.If smith gives Rs 750 to Prakash,Prakash will have twice as much as left with smith.How much each had initially?
Found 2 solutions by mangopeeler07, ankor@dixie-net.com:
Answer by mangopeeler07(462) About Me  (Show Source):
You can put this solution on YOUR website!
First set a variable to the equation. How about d? Just a random pick. Set Prakash to d and Smith to 3d, since he has 3 times as much as Prakash. You know that Smith gave Prakash 750, and now Prakash has double the amount that Smith has left.So set Prakash's new amount (d+750) equal to the double of Smith's new amount (3d-750) so set it up like this. Prakash%2B750=2Smiths+remainder. Once you plug your values in it will look like this d%2B750=2%283d-750%29. Distribute on the right side and get d%2B750=6d-1500. Then add 1500 to both sides and get d%2B2250=6d. Subtract d from each side and get 2250=5d. Then divide both sides by five. You should get d=450. After you've gotten d, you can just plug it back into Smith's and Prakash's original values, 3d and d. Once that is done, Smith had 1350 and Prakash had 450. Wanna check? Subtract subtract 750 from Smith's balance and add it to Prakash's balance. You got 600 and 1200, right? It works!

Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
Smith has three times as much money as Prakash.If smith gives Rs 750 to Prakash,Prakash will have twice as much as left with smith.How much each had initially?
:
s = 3p
:
If s gives 750 to p,
:
Then we have:
s-750
and
p+750
:
"p will have twice as much left as s."
p+750 = 2(s-750)
p+750 = 2s - 1500
p = 2s - 1500 - 750
p = 2s - 2250
:
How much each had initially?
:
Substitute 3p for s in the above equation
p = 2(3p) - 2250
+2250 = 6p - p
p = 2250%2F%285p%29
p = 450 is the initial amt
and
s = 3(450) = 1350 initial amt
:
:
Check solution in the statement:
"p will have twice as much left as s.
(450 + 750) = 2(1350 - 750)
1200 = 2(600) confirms our solutions