SOLUTION: Leo held a garage sale. He priced all the items at a dime or a quarter. His sales totaled less than $5. Write a linear inequality for this situation What is the maximum possibl

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Question 126836This question is from textbook
: Leo held a garage sale. He priced all the items at a dime or a quarter. His sales totaled less than $5.
Write a linear inequality for this situation
What is the maximum possible number of items that could have been sold for a dime?
This question is from textbook

Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!
$5.00 is 500 cents, 10d is the amount in cents received from selling d items for a dime, and 25q is the amount in cents received from selling q items for a quarter.

10d+%2B+25q+%3C+500

This could also be expressed as 0.10d+%2B+0.25q=5.00, but I happen to think decimal coefficients are messy and best avoided if possible. Then again, maybe I'm related to Monk.

The maximum number of items that could have been sold for a dime is when zero items sold for a quarter, so the inequality reduces to:

10d+%3C+500

Dividing by 10:
d+%3C+50

Since fractional parts of a dime are not allowed in this situation, the most items that could have been sold for a dime was 49, one less than 50.