Questions on Word Problems: Geometry answered by real tutors!

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Question 155485This question is from textbook Algebra I
: A rectangle is cut from the corner of a 10-inch by 10-inch of paper. The area of the remaining piece of paper is 4/5 of the area of the origianl peice of paper. If the width of the rectangle removed from the paper is 4 inches, what is the length of the rectangle?
This question is from textbook Algebra I
: A rectangle is cut from the corner of a 10-inch by 10-inch of paper. The area of the remaining piece of paper is 4/5 of the area of the origianl peice of paper. If the width of the rectangle removed from the paper is 4 inches, what is the length of the rectangle?

Answer by Earlsdon(3516) About Me  (Show Source):
You can put this solution on YOUR website!
The area of the original sheet of 10X10 sheet of paper is:
A = L*W
A = 10*10
A = 100sq.in.
The remaining area after the removal of the rectangular piece is given as:
a = (4/5)(100)
a = 80 so then, the area of the removed rectangular piece is just 100 - 80 = 20 sq.in.
The width of the removed piece is 4 inches, so, for the removed piece...
A = L*W
20 = L*(4)
L = 20/4
L = 5inches.

Question 155475: The measure of a supplement of an angle is 12 degrees greater then 3 times the measure of a complement. Find the measure of the angle.: The measure of a supplement of an angle is 12 degrees greater then 3 times the measure of a complement. Find the measure of the angle.
Answer by jojo14344(371) About Me  (Show Source):
You can put this solution on YOUR website!
Let's bisect the problem carefully.
First illustration:
A and B are supplementary angles, so A+B=180 -----> eqn 1
It shows B is a supplement of A and a highlight(condition) exist that the supplement which is B, is 12 degrees greater than 3 times the complement.
2nd illustration:
We make again A and B complementary angles this time, so
A+B=90 ----> eqn 2. we make A a complement of B. To show the condition on the 1st illustration: highlight(B=12+(3A))----> 12 greater than 3 times the complement, being A a complement of B right?
Substitute the highlight(condition) to eqn 1:
A+12+3A=180
4A=180-12=168
cross(4)A/cross(4)=cross(168)42/cross(4)
A=42degrees
For B in question via eqn 1:42+B=180
B=180-42=138degrees
To check, go back to the highlight(condition):
B=12+(3A)
138=12+(3*42)
138=12+126
138deg=138deg
Thank you,
Jojo

Question 155408: A shipping crate is to be constructed with its length six times the size of its width, and its height one-third the size of its length. The volume of the box must be 6144 cubic inches. Find the dimensions of the box.

thanks.
: A shipping crate is to be constructed with its length six times the size of its width, and its height one-third the size of its length. The volume of the box must be 6144 cubic inches. Find the dimensions of the box.

thanks.

Answer by checkley77(1745) About Me  (Show Source):
You can put this solution on YOUR website!
L=6W
H=L/3
LWH=6144
6W*W*L/3=6144
6W*W*6W/3=6144
36W^3/3=6144
12W^3=6144
W^3=6144/12
W^3=512
W=CUBERT512
W=8 FOR THE WIDTH
L=6*8=48 FOR THE LENGTH
H=48/3=16 FOR THE HEIGHT.
PROOF:
8*48*16=6144
6144=6144

Question 155392: If a coin is flipped 4 times, find P (exactly 3 heads).
My answer was 4/16 or 1/4 probability,
is is correct?
: If a coin is flipped 4 times, find P (exactly 3 heads).
My answer was 4/16 or 1/4 probability,
is is correct?

Answer by stanbon(18044) About Me  (Show Source):
You can put this solution on YOUR website!
Correct; Yes.
Cheers,
Stan H.

Question 155370: This is an extra credit question for my Honors Geometry Class-- I am in 8th grade
If a coin is flipped 4 times, find P (exactly 3 heads).
I do not know what my teacher is looking for- PLEASE HELP
THIS IS NOT A TEXTBOOK QUESTION!
: This is an extra credit question for my Honors Geometry Class-- I am in 8th grade
If a coin is flipped 4 times, find P (exactly 3 heads).
I do not know what my teacher is looking for- PLEASE HELP
THIS IS NOT A TEXTBOOK QUESTION!

Answer by stanbon(18044) About Me  (Show Source):
You can put this solution on YOUR website!
If a coin is flipped 4 times, find P (exactly 3 heads).
-------------
Write down ALL of the possible results for flipping a coin 4 times;
there are 16 patterns.
--------
hhhh
--------
hhht
hhth
hthh
thhh
--------
tthh
thth
thht
htht
hhtt
htth
----
httt
thtt
ttht
ttth
------
tttt
=========
Note: that listing is called the "sample space" for the experiment
of tossing 4 coins as it lists all the possible results.
=========
Now count the number of coutcomes that have "exactly 3 heads".
=========
The probability of exactly 3 heads is the number of outcomes that
have 3 heads divided by the total number of possible outcomes.
==============================
Cheers,
Stan H.
==============================



Question 154681: 1. A cell divides into two identical copies every 4 minutes. How many cells will exist after 3 hours? : 1. A cell divides into two identical copies every 4 minutes. How many cells will exist after 3 hours?
Answer by jojo14344(371) About Me  (Show Source):
You can put this solution on YOUR website!
By Ratio & Proportion:
Let X= # of copies:
2copies/4min=X/3hrs
2copies/4min=X/180min, cross multiply
2*180=4X
360=4X --------> cross(360)90/cross(4)=cross(4)X/cross(4)
X=90copies
Thank you,
Jojo

Question 155217: I need a little help with the following:
How many 2-inch square blocks can fit inside a rectaingle that is 10in. high by 20in long?
: I need a little help with the following:
How many 2-inch square blocks can fit inside a rectaingle that is 10in. high by 20in long?

Answer by jojo14344(371) About Me  (Show Source):
You can put this solution on YOUR website!
Area of Rectangle=A[R]=LW
A[R]=10*20=200in^2
Area of square block=A[sb]=2^2=4in^2
Therefore,
A[R]/A[sb]=200cross(in^2)/4cross(in^2)=50blocks --->#of blocks to fit
Thank you,
Jojo

Question 154567: Hi,
How would I graph the following?
g(x) = log2(x)
I wanted to post my graph of this log but I could not post it so someone could look at it.
Could you please show me how it suppose to look.
I am sorry, for the trouble.
J
: Hi,
How would I graph the following?
g(x) = log2(x)
I wanted to post my graph of this log but I could not post it so someone could look at it.
Could you please show me how it suppose to look.
I am sorry, for the trouble.
J

Answer by oscargut(506) About Me  (Show Source):

Question 154298: The length of a rectangle is 5 less than thrice its width. Find the dimensions if the area is 112 squared cm.: The length of a rectangle is 5 less than thrice its width. Find the dimensions if the area is 112 squared cm.
Answer by Alan3354(566) About Me  (Show Source):
You can put this solution on YOUR website!
The length of a rectangle is 5 less than thrice its width. Find the dimensions if the area is 112 squared cm.
---------------------------
L = 3W - 5 (The length of a rectangle is 5 less than thrice its width)
L*W = 112
Sub for L
(3W-5)*W = 112
3w^2 - 5W - 112 = 0
Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)
Quadratic equation ax^2+bx+c=0 (in our case 3x^2+-5x+-112 = 0) has the following solutons:

x[12] = (b+-sqrt( b^2-4ac ))/2\a

For these solutions to exist, the discriminant b^2-4ac should not be a negative number.

First, we need to compute the discriminant b^2-4ac: b^2-4ac=(-5)^2-4*3*-112=1369.

Discriminant d=1369 is greater than zero. That means that there are two solutions:  x[12] = (--5+-sqrt( 1369 ))/2\a.

x[1] = (-(-5)+sqrt( 1369 ))/2\3 = 7
x[2] = (-(-5)-sqrt( 1369 ))/2\3 = -5.33333333333333

Quadratic expression 3x^2+-5x+-112 can be factored:
3x^2+-5x+-112 = (x-7)*(x--5.33333333333333)
Again, the answer is: 7, -5.33333333333333. Here's your graph:
graph( 500, 500, -10, 10, -20, 20, 3*x^2+-5*x+-112 )

Ignore the negative answer, so W = 7 (the online solver always uses x)
W = 7
L = 3*7 - 5 = 16

Question 154298: The length of a rectangle is 5 less than thrice its width. Find the dimensions if the area is 112 squared cm.: The length of a rectangle is 5 less than thrice its width. Find the dimensions if the area is 112 squared cm.
Answer by jojo14344(371) About Me  (Show Source):
You can put this solution on YOUR website!
Remember:
Arect=L*W -------------------------------------> working eqn
But L=3W-5, 5 less thrice the width
So substitute,
A=(3W-5)(W), distribute
112=(3w^2-5W)
3W^2-5W-112=0
By Quadratic: a=3, b=-5, & c=-112
x=(-b+-sqrt(b^2-4ac))/(2a)
x=(-(-5)+-sqrt(-5^2-4*3*-112))/(2*3)
x=(5+-sqrt(25+1344))/6
x=(5+-sqrt(1369))/6
x=(5+-37)/6, It has 2 values:
x=(5+37)/6=7 --------------------> TO BE USED , WIDTH
x=(5-37)/6=-5.33 -----------------> DON'T USED (-)
Therefore,
L=3*7-5=21-5=16cm
W=7cm
In doubt? Go back working eqn:
A=L*W
112=16*7
112cm^2=112cm^2
Thank you,
Jojo

Question 153557: The length of a rectangle is 9 centimeters more than half the width. Find the length if they perimeter is 60 centimeters. : The length of a rectangle is 9 centimeters more than half the width. Find the length if they perimeter is 60 centimeters.
Answer by orca(258) About Me  (Show Source):
You can put this solution on YOUR website!
Let x be the width, then the length is x/2 + 9.
The perimeter = 2*width + 2*length
= 2x + 2(x/2+9)
As the perimeter is 60, we have:
2x + 2(x/2+9)=60
Solving for x, we have
2x + x + 18 = 60
3x+18=60
3x=42
x=14
So
the width is 14 cm,
the length is x/2 + 9=14/2+9=7+9=16 cm.

Question 153997: Can Someone please help me, I tried to solve this but I not sure of my answer:

Translate the following into a quadratic equation, and solve it: The length of a rectangular garden is three times its width; if the area of the garden is 75 square meters, what are its dimensions?
This is what I got I think it wrong:
3X*X=75
3X^2=75
X^2=75/3
X^2=25
X=SQRT25
X=5 ANSWER FOR THE WIDTH.
3*5=15 ANSWER FOR THE LENGTH.
15*5 = 75
I really need someone help.
Thank you,
J
: Can Someone please help me, I tried to solve this but I not sure of my answer:

Translate the following into a quadratic equation, and solve it: The length of a rectangular garden is three times its width; if the area of the garden is 75 square meters, what are its dimensions?
This is what I got I think it wrong:
3X*X=75
3X^2=75
X^2=75/3
X^2=25
X=SQRT25
X=5 ANSWER FOR THE WIDTH.
3*5=15 ANSWER FOR THE LENGTH.
15*5 = 75
I really need someone help.
Thank you,
J

Answer by checkley77(1745) About Me  (Show Source):
You can put this solution on YOUR website!
3X*X=75
3X^2=75
X^2=75/3
X^2=25
X=SQRT25
X=5 ANSWER FOR THE WIDTH.
3*5=15 ANSWER FOR THE LENGTH.
[Proof:]
15*5 = 75
What is your problem? You have a valid proof.

Question 153778: the second angle of a triangle is 30 degrees less than the first angle. the third angle is twice the second angle. how large are the angles?
please and thank you
: the second angle of a triangle is 30 degrees less than the first angle. the third angle is twice the second angle. how large are the angles?
please and thank you

Answer by orca(258) About Me  (Show Source):
You can put this solution on YOUR website!
let x be the measure of the first angle.
Then the second angle is x - 30, and the third angle is 2(x-30).
Their sum is x + (x - 30) + 2(x - 30)
As the three angles of any triangle add up to 180 degrees, we have:
x + (x - 30) + 2(x - 30)=180
Solving for x, we have:
x + x - 30 + 2x - 60 = 180
4x -90 = 180
4x = 270
x = 67.5
So
The first angle is 67.5 degrees
The second angle is x-30 = 67.5-30=37.5 degrees
The third is twice the second. so it is 2*37.5 = 75 degrees

Question 153869: One side of a triangle is four centimeters longer than the shortest side. The third side of the triangle is twice as long as the shortest side. Find the length of all the sides if the perimeter is 40 centimeters.: One side of a triangle is four centimeters longer than the shortest side. The third side of the triangle is twice as long as the shortest side. Find the length of all the sides if the perimeter is 40 centimeters.
Answer by orca(258) About Me  (Show Source):
You can put this solution on YOUR website!
Let x be the length of the shortest side.
Then the lengths of the other two sides are x + 4 and 2x.
The perimeter of the triangle is x + (x + 4) + 2x.
As the perimeter is 40, we have
x + (x + 4) + 2x = 40
Solving for x, we have
x+ x + 4 + 2x = 40
4x + 4 = 40
4x = 36
x = 9
So the length of the shortest side is 9 cm.
The lengths of the other two sides are:
x + 4 = 9 + 4 = 13 cm
2x = 2*9 = 18 cm

Question 153856: A pole vaulter uses a 15-foot-long-pole.She grips the pole so that the segment below her left hand is twice the lenght of the segment abover her left hand.Her right hand grips the pole 1.5 feet above her left hand.How far up the pole is her right hand?: A pole vaulter uses a 15-foot-long-pole.She grips the pole so that the segment below her left hand is twice the lenght of the segment abover her left hand.Her right hand grips the pole 1.5 feet above her left hand.How far up the pole is her right hand?
Answer by vleith(967) About Me  (Show Source):
You can put this solution on YOUR website!
The lefthand splits the pole's length into two pieces. One piece is twice as long as the other.
The full length is 15.
2/3 is below the lefthand, 1/3 above it.
2/3 * 15 = 10
So there her left hand is 10 feet from the far end of the pole.
The right hand is 1.5 feet above the left. So the right hand is at
10+1.5 = 11.5 from the far end.

Question 153317: Hello,
How would I graph the following:
Plot the graphs of the following functions. Scan the graphs and post them to the Facilitator along with your response.
3. f(x)=(1/5)^x
Thank you,
Jimmy
: Hello,
How would I graph the following:
Plot the graphs of the following functions. Scan the graphs and post them to the Facilitator along with your response.
3. f(x)=(1/5)^x
Thank you,
Jimmy

Answer by Fombitz(1275) About Me  (Show Source):
You can put this solution on YOUR website!
Make a table of x,f(x) data points.
Then plot the points and connect the points.
-2 ,25
-1 ,5
0 ,1
1 ,0.2
2 ,0.04
3 ,0.008
As you can see from the points as x grow large negatively, f(x) increases quickly.
Also, as x grows large positively, f(x) quickly goes to zero.
drawing( 300, 300, -5, 5, -5, 5,grid( 1 ),circle(-2	,25,0.2),<BR>
circle(-1	,5,0.1),<BR>
circle(0	,1,0.1),<BR>
circle(1	,0.2,0.1),<BR>
circle(2	,0.04,0.1),<BR>
circle(3	,0.008,0.1),<BR>
green(line( -1,5,0,1)),<BR>
green(line( 0,1,1,.2)),<BR>
green(line( 1,.2,2,.04)),<BR>
green(line( 2,.04,3,.008)),<BR>
green(line(3,.008,4,0.0)))

Question 153308: Hello,
I need help with the following:
Plot the graphs of the following functions.
1. f(x)=7x
Thank you for your help.
Sally
: Hello,
I need help with the following:
Plot the graphs of the following functions.
1. f(x)=7x
Thank you for your help.
Sally

Answer by mangopeeler07(429) About Me  (Show Source):
You can put this solution on YOUR website!
y=f(x)
f(x)=7x

First plug in a number for x. Maybe 1 first:
f(1)=7

So one point is (1,7).

Now plug in 2:
f(2)=14

So another point is (2,14).

Now plug in 3:
f(3)=21

So another point is (3,21).

Keeping plugging in numbers this way and plot them on a graph. Remember to plug in negative numbers too, such as:

f(-1)=-7
(-1,-7)

I hope this helps!

Question 153310: Hi,
I need help with the following,I tried but I not sure of my graph and I can post it for someone to look at it for me.
Could you please help me with the following:
Plot the graphs of the following functions.
2. f(x)=4x - 3
Gloria

: Hi,
I need help with the following,I tried but I not sure of my graph and I can post it for someone to look at it for me.
Could you please help me with the following:
Plot the graphs of the following functions.
2. f(x)=4x - 3
Gloria


Answer by checkley77(1745) About Me  (Show Source):
You can put this solution on YOUR website!
f(x)=4x-3
 graph( 300, 200, -6, 5, -10, 10, 4x -3) (graph 300x200 pixels, x from -6 to 5, y from -10 to 10, 4x -3).

Question 153189: Hello,
How would I solve the following:
The level of thorium in a sample decreases by a factor of one-half every 4.2 million years. A meteorite is discovered to have only 7.6% of its original thorium remaining. How old is the meteorite?
I think this has been answered but I can not find the answer.
Please help me I have tried several time to solve this without any help but I just can seen to solve it.
Thank you,
Jimmy
: Hello,
How would I solve the following:
The level of thorium in a sample decreases by a factor of one-half every 4.2 million years. A meteorite is discovered to have only 7.6% of its original thorium remaining. How old is the meteorite?
I think this has been answered but I can not find the answer.
Please help me I have tried several time to solve this without any help but I just can seen to solve it.
Thank you,
Jimmy

Answer by stanbon(18044) About Me  (Show Source):
You can put this solution on YOUR website!
The level of thorium in a sample decreases by a factor of one-half every 4.2 million years. A meteorite is discovered to have only 7.6% of its original thorium remaining. How old is the meteorite?
-------------------------
A(t) = Ao(1/2)^(t/4.2 mil)
This says "the amount at time t A(t) is the amount you start with (Ao)
multiplied by (1/2) (t/4.2 mil) times.
-------------
0.076Ao = Ao*(1/2)^(t/4.2 mil)
0.076 = (1/2)^(t/4.2 mil)
Take the log of both sides to get:
log 0.076 = (t/4.2 mil)*log(1/2)
t/4.2 mil = log0.076/log0.5
t = 4.2 mil * 3.717857...
t = 15.614998.. million years old.
================
Cheers,
Stan H.

Question 152892: Hello,
I really need help, I tried but I can not get this problem.Practical Application of Quadratic Equations Solve the questions
A rectangular garden has dimensions of 18 feet by 13 feet. A gravel path of uniform width is to be built around the garden. How wide can the path be if there is enough gravel for 516 square feet?
Thank you so much,
Sally

: Hello,
I really need help, I tried but I can not get this problem.Practical Application of Quadratic Equations Solve the questions
A rectangular garden has dimensions of 18 feet by 13 feet. A gravel path of uniform width is to be built around the garden. How wide can the path be if there is enough gravel for 516 square feet?
Thank you so much,
Sally


Answer by scott8148(2485) About Me  (Show Source):
You can put this solution on YOUR website!
let x="width of path"

area of garden is 18*13 or 234 __ area of garden plus path is 234+516 or 750

(18+2x)(13+2x)=750 __ 234+62x+4x^2=750 __ dividing by 2 __ 2x^2+31x+117=375 __ subtracting 375 __ 2x^2+31x-258=0

factoring __ (2x+43)(x-6)=0

2x+43=0 __ x=-43/2 __ negative value not realistic

x-6=0 __ x=6

Question 152894: Hello,
Sorry to bother you again but I can seem to grasp the following to put into an equation. It from Practical Application of Quadratic Equations Solve the questions
A business invests $10,000 in a savings account for two years. At the beginning of the second year, an additional $3500 is invested. At the end of the second year, the account balance is $15,569.75. What was the annual interest rate?
Thank you,
Craig
: Hello,
Sorry to bother you again but I can seem to grasp the following to put into an equation. It from Practical Application of Quadratic Equations Solve the questions
A business invests $10,000 in a savings account for two years. At the beginning of the second year, an additional $3500 is invested. At the end of the second year, the account balance is $15,569.75. What was the annual interest rate?
Thank you,
Craig

Answer by scott8148(2485) About Me  (Show Source):
You can put this solution on YOUR website!
end of 1st yr __ 10000(1+r)

end of 2nd yr __ [10000(1+r)+3500](1+r)=15569.75

10000+10000r+3500+10000r+10000r^2+3500r=15569.75 __ subtracting 15569.75 __ 10000r^2+23500r-2069.75=0

use quadratic formula to find r


r=8.5%

Question 152833: Hello,
I stuck I have the following quadratic equations but I having trouble trying to figure it out.
If x = 1 and x = -8, then form a quadratic equation.
Thank you so much for your help.
Jimmy
: Hello,
I stuck I have the following quadratic equations but I having trouble trying to figure it out.
If x = 1 and x = -8, then form a quadratic equation.
Thank you so much for your help.
Jimmy

Answer by Fombitz(1275) About Me  (Show Source):
You can put this solution on YOUR website!
If x=1 and x=-8 are zeros for a quadratic equation, then they satisfy,
x-1=0
x+8=0
The simplest quadratic equation would be the two left hand sides multiplied together.
(x-1)(x+8)=0
Using the FOIL method we can expand the left hand side,
(x-1)(x+8)=0
x^2+8x-x-8=0
x^2+7x-8=0

Question 152486: Hi,
How would I solve the following: Applications of Linear Equations
An express and local train leave Gray’s Lake at 3 P.M. and head for Chicago 50 miles away. The express travels twice as fast as the local, and arrives 1 hour ahead of it. Find the speed of each train.
Thank you so much for your help.
K.
: Hi,
How would I solve the following: Applications of Linear Equations
An express and local train leave Gray’s Lake at 3 P.M. and head for Chicago 50 miles away. The express travels twice as fast as the local, and arrives 1 hour ahead of it. Find the speed of each train.
Thank you so much for your help.
K.

Answer by ankor@dixie-net.com(3949) About Me  (Show Source):
You can put this solution on YOUR website!
An express and local train leave Gray’s Lake at 3 P.M. and head for Chicago 50 miles away. The express travels twice as fast as the local, and arrives 1 hour ahead of it. Find the speed of each train.
;
Let s = speed of the local train
then
2s = speed of the express
:
Write a time equation: Time = dist/speed
:
Local time - express time = 1 hr
50/s - 50/(2s) = 1
Multiply equation by 2s to get rid of the denominators
2s*50/s - 2s*50/(2s) = 2s(1)
Results
2(50) - 50 = 2s
:
100 - 50 = 2s
s = 50/2
s = 25 mph speed of the local, obviously, 50 mph is speed of express
:
:
Check solution in our time equation:
50/25 - 50/(50) = 1
2 - 1 = 1
:
:
Pretty easy, right?

Question 152521: Hi,
How would I solve the following: Applications of Linear Equations
An express and local train leave Gray’s Lake at 3 P.M. and head for Chicago 50 miles away. The express travels twice as fast as the local, and arrives 1 hour ahead of it. Find the speed of each train.
Thank you so much for your help.
Sally
: Hi,
How would I solve the following: Applications of Linear Equations
An express and local train leave Gray’s Lake at 3 P.M. and head for Chicago 50 miles away. The express travels twice as fast as the local, and arrives 1 hour ahead of it. Find the speed of each train.
Thank you so much for your help.
Sally

Answer by Fombitz(1275) About Me  (Show Source):
You can put this solution on YOUR website!
Rate times time equals distance.
The express train travels at a rate of R[e] and takes t[e] to travel the 50 miles.
1.R[e]*t[e]=50
The local train travels at a rate of R[l] and takes t[l] to travel the 50 miles.
2.R[l]*t[l]=50
You also know that the rate of the express train is twice the rate of the local train.
R[e]=2*R[l]
And finally you know that the local train arrived 1 hour after the express train.
t[l]=t[e]+1
From 2,
2.R[l]*t[l]=50
Substitute for R[l] and t[l]
2.R[l]*t[l]=50
(1/2)*R[e]*(t[e]+1)=50
R[e]*(t[e]+1)=100
R[e]*t[e]+R[e]=100
From 1, you know that R[e]*t[e]=50
R[e]*t[e]+R[e]=100
50+R[e]=100
R[e]=50
The express train travels at 50 miles per hour.
From 1,
R[e]*t[e]=50
50*t[e]=50
t[e]=1
The express train takes 1 hour to reach Chicago.
R[e]=2*R[l]
50=2*R[l]
R[l]=25
The local train travels 25 miles per hour.
t[l]=t[e]+1
t[l]=1+1
t[l]=2
The local train takes 2 hours to reach Chicago.

Question 152485: Hi,
How would I solve the following: Applications of Linear Equations

Joe has a collection of nickels and dimes that is worth $5.65. If the number of dimes were doubled and the number of nickels were increased by 8, the value of the coins would be $10.45. How many dimes does he have?
Thank you for helping me.
J.
: Hi,
How would I solve the following: Applications of Linear Equations

Joe has a collection of nickels and dimes that is worth $5.65. If the number of dimes were doubled and the number of nickels were increased by 8, the value of the coins would be $10.45. How many dimes does he have?
Thank you for helping me.
J.

Answer by scott8148(2485) About Me  (Show Source):
You can put this solution on YOUR website!
let d=dimes, n=nickels

"Joe has a collection of nickels and dimes that is worth $5.65" __ 10d+5n=565

"If the number of dimes were doubled and the number of nickels were increased by 8, the value of the coins would be $10.45"
__ 10(2d)+5(n+8)=1045 __ 20d+5n+40=1045 __ 20d+5n=1005

subtracting equations __ (20d+5n)-(10d+5n)=1005-565 __ 10d=440 __ d=44

Question 152448: The width of a rectangle is 2/3 of its length. Find its length if the perimeter is 80 cm. Find the dimensions.
: The width of a rectangle is 2/3 of its length. Find its length if the perimeter is 80 cm. Find the dimensions.

Answer by jojo14344(371) About Me  (Show Source):
You can put this solution on YOUR website!
P=2(L+W) --------------------> eqn 1
But, W=(2/3)L, so
P=2(L+(2/3)L)
80cm=2((3L+2L)/3)), adding & cross multiply
(80*3)/2=5L
120=5L ---------> cross(120)24/cross(5)=cross(5)L/cross(5)
L=24cm
And, W=(2/3)24=16cm
In doubt? Go back eqn 1:
80cm=2(24cm+16cm)
80cm=2(40cm)
80cm=80cm
Thank you,
Jojo

Question 152487: Hi,
How would I solve the following: Applications of Linear Equations
Walt made an extra $9000 last year from a part-time job. He invested part of the money at 9% and the rest at 8%. He made a total of $770 in interest. How much was invested at 8%?
Thank you for taking the time to help me.
Sally
: Hi,
How would I solve the following: Applications of Linear Equations
Walt made an extra $9000 last year from a part-time job. He invested part of the money at 9% and the rest at 8%. He made a total of $770 in interest. How much was invested at 8%?
Thank you for taking the time to help me.
Sally

Answer by Earlsdon(3516) About Me  (Show Source):
You can put this solution on YOUR website!
G'day Sally;
Let x = the amount invested at 8% and the remainder ($9000-x) is invested at 9%
The amount of interest earned on these amounts can be expressed as:
x(0.08) This is amount earned at 8%.
($9000-x)(0.09) This is the amount earned at 9%
The sum (+) of these two amounts is given as $770.00, so you can write the equation to solve for x, the amount invested at 8%
(0.08)x + (0.09)($9000-x) = $770 Simplify and solve for x.
0.08x + $810 - 0.09x = $770 Subtract $810 from both sides.
0.08x-0.09x = -$40 Combine the x's on the left side.
-0.01x = -$40 Finally, divide both sides by -0.01 to get x by itself.
x = $4000
So $4000 was invested at 8% and $9000-$4000 = $5000 was invested at 9%
Let's check the solution:
0.08($4000) + 0.09($5000) = $320 + $450 = $770 The total interest earned.

Question 151166This question is from textbook
: if angle A is a right angle and the measure of angle C=3x and measure of angle ABC=2x, find the measure of each interior angle and what is the value of x?This question is from textbook
: if angle A is a right angle and the measure of angle C=3x and measure of angle ABC=2x, find the measure of each interior angle and what is the value of x?
Answer by orca(258) About Me  (Show Source):
You can put this solution on YOUR website!
Use the fact that the sum of the interior angles of any triangle is equal to 180 degrees to set up an equation
Here, < A=90, < B=2x and < C=3x,their sum is 90+2x+3x.
Setting it equal to 180,we have
90+2x+3x=180
Solving for x,we obtain:
90 + 5x = 180
5x = 90
x = 18
therefore
< B= 2x = 2*18 = 36 degrees
< C = 3x = 3*18 = 54 degrees.

Question 152386: A, B, C, and D are distinct coplanar points, no 3 of which are collinear. If E is a point not in the plane of A, B, C, and D, how many distinct planes are determined by the 5 points?
a. 4
b. 5
c. 6
d. 7
Which answer is correct and why?
: A, B, C, and D are distinct coplanar points, no 3 of which are collinear. If E is a point not in the plane of A, B, C, and D, how many distinct planes are determined by the 5 points?
a. 4
b. 5
c. 6
d. 7
Which answer is correct and why?

Answer by Earlsdon(3516) About Me  (Show Source):
You can put this solution on YOUR website!
Think about this!
Through any three non-collinear points, there is exactly one plane!
The planes that you identify here must include the point E, so you can list all of the possible combinations of the points, A, B, C, D, with the point E.
E,A,B
E,A,C
E,A,D
E,B,C
E,B,D
E,C,D
So it seems that there are 6 distinct planes determined by the five points if point E is to be included in each one.

Question 152354: Hi,
Can someone please review the following, I did the work I just want to make sure it correct before I submit it.
Thank you for your help.
From the given polynomials, identify the polynomials of degree one.
a. 311y - 5 - 43y Since degree is based on the power of the largest variable (or is degree 0 if everything is constants). You have an expression that contains y to a power of 1. So the degree is 1
b. (11y2)1/2 + 14 ( This is a degree 2)
c. 10 + (19)1/2x (This is not a polynomial)
d. 2 + 15x ( This is a degree 1 polynomial)
e. 52y4 + 7x + 2 ( This is not a polynomial)
f. (68)1y1 (This is a degree 1 polynomial)
g. x3 + 3x – 9 ( This is a degree 3 )
h. (2x)1/2 + 4x – 8 (This is a degree 1)

Solve the following:
1. -2x = 3x + 4
-2x = 3x + 4

5x=4 --------> -5*x/5 = 4/(-5)


= -4
5


2. 3x/4 = 6
3x=6*4 , cross multiply:

3x=24 --------> 3*x= 24*8/3 eliminate 3 and 24
x=8

3. y/6 + 1 = 9
y/6 + 1 = 9

y+6/6=9, cross multiply,

y+6=54
y=54-6
y= 48
6 = -2x/4 , cross multiply,
24= -2x -------> 24 * 12/-2 = -2*x/-2 eliminate like terms 24,-2,-2,-2
x= -12

4. 6 = -2x/4
6 = -2x/4
-2x=6*4
-2x=24
x=24/-2
Answer: x=-12
To proof it I did the following:
6=-2*-12/4
6=24/4
6=6

5. Find f(1) for f(x) = 4x3 - 3x2 - x + 2
The problem gives you a "function of x":
f(x) = 4x3 - 3x2 - x + 2
.
Now, to find f(1), it simply asks you to find the value of f(x) when x=1
.
So I , simply substitute in 1 wherever I see the x and solve:
f(x) = 4x^3 - 3x^2 - x + 2
Substituting I get:
f(1) = 4(1)^3 - 3(1)^2 - 1 + 2
f(1) = 4(1) - 3(1) - 1 + 2
f(1) = 4 - 3 - 1 + 2
f(1) = 6 - 4
f(1) = 2 (so f(1)=2)
Answer: f(1)=2
6. A function gives the value of C as 2 × (22/7) × r. Find C when r = 21 cm and r = 84 cm.
plug in 21 for r:
C = 2 × (22/7) × 21
Answer: C = 132 cm
And plug in 84:
C = 2 × (22/7) × 84
Answer: C = 528 cm
: Hi,
Can someone please review the following, I did the work I just want to make sure it correct before I submit it.
Thank you for your help.
From the given polynomials, identify the polynomials of degree one.
a. 311y - 5 - 43y Since degree is based on the power of the largest variable (or is degree 0 if everything is constants). You have an expression that contains y to a power of 1. So the degree is 1
b. (11y2)1/2 + 14 ( This is a degree 2)
c. 10 + (19)1/2x (This is not a polynomial)
d. 2 + 15x ( This is a degree 1 polynomial)
e. 52y4 + 7x + 2 ( This is not a polynomial)
f. (68)1y1 (This is a degree 1 polynomial)
g. x3 + 3x – 9 ( This is a degree 3 )
h. (2x)1/2 + 4x – 8 (This is a degree 1)

Solve the following:
1. -2x = 3x + 4
-2x = 3x + 4

5x=4 --------> -5*x/5 = 4/(-5)


= -4
5


2. 3x/4 = 6
3x=6*4 , cross multiply:

3x=24 --------> 3*x= 24*8/3 eliminate 3 and 24
x=8

3. y/6 + 1 = 9
y/6 + 1 = 9

y+6/6=9, cross multiply,

y+6=54
y=54-6
y= 48
6 = -2x/4 , cross multiply,
24= -2x -------> 24 * 12/-2 = -2*x/-2 eliminate like terms 24,-2,-2,-2
x= -12

4. 6 = -2x/4
6 = -2x/4
-2x=6*4
-2x=24
x=24/-2
Answer: x=-12
To proof it I did the following:
6=-2*-12/4
6=24/4
6=6

5. Find f(1) for f(x) = 4x3 - 3x2 - x + 2
The problem gives you a "function of x":
f(x) = 4x3 - 3x2 - x + 2
.
Now, to find f(1), it simply asks you to find the value of f(x) when x=1
.
So I , simply substitute in 1 wherever I see the x and solve:
f(x) = 4x^3 - 3x^2 - x + 2
Substituting I get:
f(1) = 4(1)^3 - 3(1)^2 - 1 + 2
f(1) = 4(1) - 3(1) - 1 + 2
f(1) = 4 - 3 - 1 + 2
f(1) = 6 - 4
f(1) = 2 (so f(1)=2)
Answer: f(1)=2
6. A function gives the value of C as 2 × (22/7) × r. Find C when r = 21 cm and r = 84 cm.
plug in 21 for r:
C = 2 × (22/7) × 21
Answer: C = 132 cm
And plug in 84:
C = 2 × (22/7) × 84
Answer: C = 528 cm

Answer by Earlsdon(3516) About Me  (Show Source):
You can put this solution on YOUR website!
All of your answers look good except for the first problem, part e.
Given: 52y^4+7x+2 ...You said "This is not a polynomial" Why is it not?
It certainly qualifies as a polynomial (a trinomial in this case) because there are no terms with variables in the denominator and no terms with variables under a radical sign.
This polynomial is of degree 4 because of the 52y^4

Question 152325: A photo is 3 inches longer than it is wide. A 2-inch border is placed around the photo making the total area of the photo and border 108 square inches. Wat are the dimensions of the photo. : A photo is 3 inches longer than it is wide. A 2-inch border is placed around the photo making the total area of the photo and border 108 square inches. Wat are the dimensions of the photo.
Answer by jojo14344(371) About Me  (Show Source):
You can put this solution on YOUR website!
Same as Problem#151709
See ANSWER# 111525
Thank you,
Jojo

Question 152166: Hi,
I need help with the following could someone please help me.
How would I solve the following:
A function gives the value of C as 2 × (22/7) × r. Find C when r = 21 cm and r = 84 cm.
Thank you for your help.
J.
: Hi,
I need help with the following could someone please help me.
How would I solve the following:
A function gives the value of C as 2 × (22/7) × r. Find C when r = 21 cm and r = 84 cm.
Thank you for your help.
J.

Answer by jojo14344(371) About Me  (Show Source):
You can put this solution on YOUR website!
A function gives the value of C as 2 × (22/7) × r. Find C when r = 21 cm and r = 84 cm.
C=2*(22/7)*r
C has 2 values:
1st, r= 21cm
C=2*(22/7)*(21cm)
C=132cm
2nd, r=84cm
C=2*(22/7)*(84cm)
C=528cm
Thank you,
Jojo

Question 152234: A rectangular parking lot is 100 ft longer than it is wide. Determine the dimensions of the parking lot if it measures 500 ft diagonally.: A rectangular parking lot is 100 ft longer than it is wide. Determine the dimensions of the parking lot if it measures 500 ft diagonally.
Answer by nerdybill(465) About Me  (Show Source):
You can put this solution on YOUR website!
A rectangular parking lot is 100 ft longer than it is wide. Determine the dimensions of the parking lot if it measures 500 ft diagonally.
.
Let x = width
x+100 = length
.
Applying Pythagorean theorem:
x^2 + (x+100)^2 = 500^2
x^2 + x^2 + 200x + 10000 = 250000
2x^2 + 200x - 240000 = 0
x^2 + 100x - 120000 = 0
.
Factoring we get:
(x-300)(x+400) = 0
x = {-400, 300}
Only the positive answer makes sense so
x = 300 feet (width)
.
x+100 = 400 feet (length)
.
Conclusion:
parking lot is 300 feet by 400 feet

Question 152181: Hi,
How would I figure the following:Ratio and Proportion
A lawyer bills her clients $200 per hour of service. If a client's case requires 39 hours to complete, use proportion to calculate how much the client will owe the lawyer (excluding tax).
Thank you for taking the time out of your day to help me.
Marty
: Hi,
How would I figure the following:Ratio and Proportion
A lawyer bills her clients $200 per hour of service. If a client's case requires 39 hours to complete, use proportion to calculate how much the client will owe the lawyer (excluding tax).
Thank you for taking the time out of your day to help me.
Marty

Answer by nerdybill(465) About Me  (Show Source):
You can put this solution on YOUR website!
A lawyer bills her clients $200 per hour of service. If a client's case requires 39 hours to complete, use proportion to calculate how much the client will owe the lawyer (excluding tax).
.
From: "A lawyer bills her clients $200 per hour of service." we get the ratio:
$200:1 hour
.
From: "a client's case requires 39 hours to complete" we get the ratio:
Let x = how much the client owes
x: 39 hours
.
Therefore we have:
200/1 = x/39
Cross multiplying we get:
200 * 39 = x
$7800 = x

Question 152169: Hi,
I need help with the following. What degree of polynomial is the following:
(68)1y^1

Thank you,
J.
: Hi,
I need help with the following. What degree of polynomial is the following:
(68)1y^1

Thank you,
J.

Answer by edjones(2169) About Me  (Show Source):
You can put this solution on YOUR website!
1st degree because y is to the power of one.

Question 152184: Hi
How would I determine the degree of the following polynomial:
(68)1y^1

I solve the following can you tell me if it right I have been out of school for 15years and I not sure of these problems:
vi. A function gives the value of C as 2 × (22/7) × r. Find C when r = 21 cm and r = 84 cm.
First I plug in 21 for r:
C = 2 × (22/7) × 21
C = 132 cm
And plug in 84:
C = 2 × (22/7) × 84
C = 528 cm
Thank you for your Help
: Hi
How would I determine the degree of the following polynomial:
(68)1y^1

I solve the following can you tell me if it right I have been out of school for 15years and I not sure of these problems:
vi. A function gives the value of C as 2 × (22/7) × r. Find C when r = 21 cm and r = 84 cm.
First I plug in 21 for r:
C = 2 × (22/7) × 21
C = 132 cm
And plug in 84:
C = 2 × (22/7) × 84
C = 528 cm
Thank you for your Help

Answer by edjones(2169) About Me  (Show Source):

Question 152094: Hi, I need help how would I find the degree of one. From the given polynomials, identify the polynomials of degree one
b. (11y2)1/2 + 14
c. 10 + (19)1/2x

d. 2 + 15x
e. 52y4 + 7x + 2

f. (68)1y1
g. x3 + 3x – 9

h. (2x)1/2 + 4x - 8
: Hi, I need help how would I find the degree of one. From the given polynomials, identify the polynomials of degree one
b. (11y2)1/2 + 14
c. 10 + (19)1/2x

d. 2 + 15x
e. 52y4 + 7x + 2

f. (68)1y1
g. x3 + 3x – 9

h. (2x)1/2 + 4x - 8

Answer by oscargut(506) About Me  (Show Source):
You can put this solution on YOUR website!
b. (11y2)1/2 + 14 (degree 2)
c. 10 + (19)1/2x (is not a polynomial)
d. 2 + 15x (degree 1)
e. 52y4 + 7x + 2 (is not a polynomial)
f. (68)1y1
g. x3 + 3x – 9 (degree 3)
h. (2x)1/2 + 4x - 8 (degree 1)

Question 152092: Hi,
How would I solve the following: Linear Equations and their Solutions
Find f(1) for f(x) = 4x3 - 3x2 - x + 2
Thank you,
Sally
: Hi,
How would I solve the following: Linear Equations and their Solutions
Find f(1) for f(x) = 4x3 - 3x2 - x + 2
Thank you,
Sally

Answer by nerdybill(465) About Me  (Show Source):
You can put this solution on YOUR website!
The problem gives you a "function of x":
f(x) = 4x3 - 3x2 - x + 2
.
Now, to find f(1), it simply asks you to find the value of f(x) when x=1
.
So, simply substitute in 1 wherever you see the x and solve:
f(x) = 4x^3 - 3x^2 - x + 2
Substituting we get:
f(1) = 4(1)^3 - 3(1)^2 - 1 + 2
f(1) = 4(1) - 3(1) - 1 + 2
f(1) = 4 - 3 - 1 + 2
f(1) = 6 - 4
f(1) = 2 (this is what they want)


Question 152016: A cube of white chalk is painted red and cut parallel to a pair of parallel size to form two rectangular solid of equal volume. What percentage of the surface area of each of the new solid is not painted red.
: A cube of white chalk is painted red and cut parallel to a pair of parallel size to form two rectangular solid of equal volume. What percentage of the surface area of each of the new solid is not painted red.

Answer by jojo14344(371) About Me  (Show Source):
You can put this solution on YOUR website!
Answer: 20% of surface area of each is not painted
Proof:
Before it was cut into half, all the sides are equal right? (a cube is a square with 3-D body). Then it was cut to half and became a rectangular solid. One side of which is not painted.
We have to remember Surface Area of a rectangular solid:
SA=2LH+2LW+2WH ---------------------> EQN 1
Important: before it has ALL SIDES EQUAL, and when cut into half there appears now the Length and the Width----> the dimensions of the Width now will be half of the Length: W=(1/2)L, Also the Height remains the same as the Length. Only the Width changed when cut into half.
For the Area of the new rectangular solid, since one side is NOT painted, SA[new]=2LH+1LW+2WH -------------------> EQN 2
NOW, IF YOU PLUG IN VALUES IN EQN 1 AND EQN 2, REMEMBER L=H, W=(1/2)<BR>
L and make (EQN2/EQN)-1). Get ABSOLUTE VALUE (no negative)*100% ----------> PERCENTAGE of Surface Area NOT painted.
Hope this helps.
Thank you,
Jojo

Question 151781: a. The measure of angle CBD is 10 less than twice the measure of angle ABD. If D is in the interior of angle ABC and the measure of angle ABC is 80, what is the measure of angle CBD?: a. The measure of angle CBD is 10 less than twice the measure of angle ABD. If D is in the interior of angle ABC and the measure of angle ABC is 80, what is the measure of angle CBD?
Answer by jojo14344(371) About Me  (Show Source):
You can put this solution on YOUR website!
We take the 1st condition: a. The measure of angle CBD is 10 less than twice the measure of angle ABD.
CBD=2ABD-10 -----------------------> eqn 1
Since D is in the interior of angle ABC, there forms an angle ABD right? Therefore, angle CBD=ABC-ABD, see the correlation there?
It's better you draw it to follow the interpretation better.
Since ABC=80deg, then CBD=80-ABD ---------------------> eqn 2
.
Equating the 2 eqns:
2ABD-10=80-ABD
2ABD+ABD=80+10
cross(3)ABD/cross(3)=cross(90)30/cross(3)
ABD=30deg
Go back eqn 2:
CBD=80-30
CBD=50deg -----------------> FINAL ANSWER
IN doubt? go back eqn 1:
50=2(30)-10
50=60-10
50=50 cool,
Thank you,
Jojo

Question 151790: Hi,
I need help with the following: I did the work just want to make sure its right
.Explain how to apply elimination in solving a system of equations.

To solve a system of linear equation by elimination process
1)Bring the co-efficient of any one variable to the same .
2) If the signs of both variable are same (having the same co-efficient) then subtract the two equation's.
a. Explain how to apply substitution in solving a system of equations.
3)If the signs are different then add the two equation’s so that like terms get eliminated.

4)The value of one variable is calculated

5)By substituting the value of known variable unknown variable can be found.
a. Demonstrate each technique in solving the system
3x + 9y = 12
5x - 4y = 3
Solution: 1. 3x + 9y = 12
2. 5x - 4y = 3
1)L.C.M of 3,5 = 15 hence bring the co-efficient of x to 15
multiply equations(1) by 5 , and equations(2) by 3. The two equations
reduces to 15x+45y = 60
15x-12y = 9
2) subtract the two equations we get 57y = 51 , y = 51/57
3) substituting the value of y in equations


(1) we get

3x+9(51/57) = 12
3x = 12- (459/57) = 684-459/57 = 225/57
x = 225/57*3 = 75/57
solution is x = 75/57 and y = 51/57

Thank you for your help.
S
: Hi,
I need help with the following: I did the work just want to make sure its right
.Explain how to apply elimination in solving a system of equations.

To solve a system of linear equation by elimination process
1)Bring the co-efficient of any one variable to the same .
2) If the signs of both variable are same (having the same co-efficient) then subtract the two equation's.
a. Explain how to apply substitution in solving a system of equations.
3)If the signs are different then add the two equation’s so that like terms get eliminated.

4)The value of one variable is calculated

5)By substituting the value of known variable unknown variable can be found.
a. Demonstrate each technique in solving the system
3x + 9y = 12
5x - 4y = 3
Solution: 1. 3x + 9y = 12
2. 5x - 4y = 3
1)L.C.M of 3,5 = 15 hence bring the co-efficient of x to 15
multiply equations(1) by 5 , and equations(2) by 3. The two equations
reduces to 15x+45y = 60
15x-12y = 9
2) subtract the two equations we get 57y = 51 , y = 51/57
3) substituting the value of y in equations


(1) we get

3x+9(51/57) = 12
3x = 12- (459/57) = 684-459/57 = 225/57
x = 225/57*3 = 75/57
solution is x = 75/57 and y = 51/57

Thank you for your help.
S

Answer by vleith(967) About Me  (Show Source):
You can put this solution on YOUR website!
You have the correct answers.
You can easily check you answers by just plugging the value for x and y into the original two equations and verifying the result is "true" (that is 12=12 and 3=3)

Question 151793: Hi,
I need help with the following:
1. From the given polynomials, identify the polynomials of degree one.
a. 311y - 5 - 43y
: Hi,
I need help with the following:
1. From the given polynomials, identify the polynomials of degree one.
a. 311y - 5 - 43y

Answer by vleith(967) About Me  (Show Source):
You can put this solution on YOUR website!
degree is based on the power of the largest variable (or is degree 0 if everything is constants).
You have an expression that contains y to a power of 1. So the degree is 1

Question 151799: A dog owner has 250 feet of fencing to enclose a rectangular run for his dogs. If he wants the maximum possible area, what should the length and width of the rectangle be?: A dog owner has 250 feet of fencing to enclose a rectangular run for his dogs. If he wants the maximum possible area, what should the length and width of the rectangle be?
Answer by Earlsdon(3516) About Me  (Show Source):
You can put this solution on YOUR website!
Let's start with the formulas for the area and the perimeter of a rectangle.
A = L*W
P = 2(L+W)
The perimeter is given as 250 feet, so we can write:
2(L+W) = 250 Dividing both sides by 2, we get:
L+W = 125 Rewrite this as:
L = 125-W and substitute it into the formula for the area (A = L*W),
A = (125-W)*W Simplifying this, we get:
A - 125W-W^2 Now this is a quadratic equation and if you were to graph this, you see a parabola that opens downward, thus there would be a maximum value of A (also known as the vertex).
You can find the value of W at this vertex by:
W = (-b)/2a This comes from the standard form for a quadratic equation:y = ax^2+bx+c
In this problem, a = -1 and b = 125, so, making the appropriate substitutions, we get:
W = (-125)/2(-1)
W = 62.5 Now this is the value of W (the width) that would make the area (A) a maximum.
The length (L) is:
L = 125-W
L = 125-62.5
L = 62.5
So the length and the width of the rectangle would be L = 62.5 feet and W = 62.5 feet. In other words, the rectangle is a square.

Question 151789: Hi,
I need help with the following:
Translate the following into a system of equations, then solve it:A customer walks into an electronics store and buys five MP3 players and eight sets of headphones, paying $840. A second customer buys three MP3 players and four sets of headphones, and pays $480. How much does an MP3 player cost? How much does a set of headphones cost?
: Hi,
I need help with the following:
Translate the following into a system of equations, then solve it:A customer walks into an electronics store and buys five MP3 players and eight sets of headphones, paying $840. A second customer buys three MP3 players and four sets of headphones, and pays $480. How much does an MP3 player cost? How much does a set of headphones cost?

Answer by jojo14344(371) About Me  (Show Source):
You can put this solution on YOUR website!
Let us see the situations:
1st customer:
5MP+8HP=$840 ----------------> eqn 1
2nd customer:
3MP+4HP=$480 ----------------> eqn 2
In eqn 2 we get, HP=(480-3MP)/4 and substitute in eqn 1:
5MP+cross(8)2(480-3MP)/cross(4)=840
5MP+960-6MP=840
960-840=6MP-5MP
MP=120 ----------------------> cost of an MP3 player
For Head phones set, go back eqn 2:
3*120+4HP=480
HP=(480-360)/4
HP=30
In doubt? Go back eqn 1:
5(120)+8(30)=840
600+240=840
840=840
Thank you,
Jojo