Questions on Word Problems: Evaluation, Substitution answered by real tutors!

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Question 152624: First equation is x + y = 56
Second equation is where I am having the problem with interperting:
The sales representative later indicates that there are 3 times as many homes available with second floor plan than the first. Write an equation that illustrates this situation. Heres what I think the secon equation should look like: x + 3y =0?
When trying to solve with substitution my answers become false.
y= -x + 56 x + 3(-x + 56)= 0
x -3x + 168 = 0
-2x + 168 = 0
-2x = -168
x = 84
y= 84 + 56
y= 140
x + y = 56
84 + 140= 196



: First equation is x + y = 56
Second equation is where I am having the problem with interperting:
The sales representative later indicates that there are 3 times as many homes available with second floor plan than the first. Write an equation that illustrates this situation. Heres what I think the secon equation should look like: x + 3y =0?
When trying to solve with substitution my answers become false.
y= -x + 56 x + 3(-x + 56)= 0
x -3x + 168 = 0
-2x + 168 = 0
-2x = -168
x = 84
y= 84 + 56
y= 140
x + y = 56
84 + 140= 196




Answer by Fombitz(1755) About Me  (Show Source):
You can put this solution on YOUR website!
Which is x and which is y?
If x is the number of homes with first floor plan and y is the number of homes with second floor plan, then
"3 times as many homes available with second floor plan than the first" would be
1.y=3x
Then
2.x+y=56
would be the total number of homes with first and second floor plans is 56.
You would have two equations with two unknowns, x and y.
You could then solve for x and then y substituting eq. 1 into eq. 2.
Please repost if you need more help.