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Tutors Answer Your Questions about Age Word Problems (FREE)
Question 168973: What is John's age now, if in twenty-six years he will be three times his present age?: What is John's age now, if in twenty-six years he will be three times his present age?
Answer by josmiceli(2029)  (Show Source): |
Question 168965: A man 38 years old has a son who is 14 years old. How many years ago was the father seven times as old as his son?: A man 38 years old has a son who is 14 years old. How many years ago was the father seven times as old as his son?
Answer by ankor@dixie-net.com(4508) (Show Source):
You can put this solution on YOUR website!A man 38 years old has a son who is 14 years old. How many years ago was the
father seven times as old as his son?
:
Let x = no. of year for this to be true
:
38 - x = 7(14 - x)
:
38 - x = 98 - 7x
:
-x + 7x = 98 - 38
:
6x = 60
:
x = 10 yrs ago
;
:
Check solution
38 - 10 = 7(14 - 10)
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Question 168965: A man 38 years old has a son who is 14 years old. How many years ago was the father seven times as old as his son?: A man 38 years old has a son who is 14 years old. How many years ago was the father seven times as old as his son?
Answer by nerdybill(1052) (Show Source):
You can put this solution on YOUR website! A man 38 years old has a son who is 14 years old. How many years ago was the father seven times as old as his son?
.
Let x = number of years ago when father was 7 times older than his son
.
38-x = 7(14-x)
38-x = 98-7x
38+6x = 98
6x = 60
x = 10 years
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Question 168797: Heather is two-thirds as old as she will be eight years before she is twice as old as she is now. How old is Heather?: Heather is two-thirds as old as she will be eight years before she is twice as old as she is now. How old is Heather?
Answer by Mathtut(373) (Show Source): |
Question 168564: I was talking to a friend Tammy, the middle child of five. She has a younger sister
Tracey, and three brothers Tommy (oldest child), Timmy and Tony (youngest child). I
asked her how old she was, but she hardly ever gives a straight answer. The following is
the conversation we had.
"How old are you Tammy?"
"I am three times as old as Timmy was when Tony was born. Actually, it's funny, but
Timmy's, Tracey's, Tommy's and my ages were all factors of Mum's age when Tony was
born. The only other year where the ages of more than two of us were factors of Mum's
age was when Tracey was half as old as I am now."
"How old is your Mum now?"
"There's another funny thing. When Mum turns 50, Tony will be the same age Mum was
when she gave birth to Tommy."
Assuming Tammy was talking in terms of whole years, and with my mathematical and reasoning abilities I was able to quickly deduce not just Tammy's age, but all of their ages. So how old are Tommy, Timmy, Tammy, Tracey, Tony and Mum now?
: I was talking to a friend Tammy, the middle child of five. She has a younger sister
Tracey, and three brothers Tommy (oldest child), Timmy and Tony (youngest child). I
asked her how old she was, but she hardly ever gives a straight answer. The following is
the conversation we had.
"How old are you Tammy?"
"I am three times as old as Timmy was when Tony was born. Actually, it's funny, but
Timmy's, Tracey's, Tommy's and my ages were all factors of Mum's age when Tony was
born. The only other year where the ages of more than two of us were factors of Mum's
age was when Tracey was half as old as I am now."
"How old is your Mum now?"
"There's another funny thing. When Mum turns 50, Tony will be the same age Mum was
when she gave birth to Tommy."
Assuming Tammy was talking in terms of whole years, and with my mathematical and reasoning abilities I was able to quickly deduce not just Tammy's age, but all of their ages. So how old are Tommy, Timmy, Tammy, Tracey, Tony and Mum now?
Answer by Mathtut(373) (Show Source): |
Question 168095: I am 6 years older than my sister.How old will I be when I am 3 times older than she?: I am 6 years older than my sister.How old will I be when I am 3 times older than she?
Answer by nerdybill(1052) (Show Source):
You can put this solution on YOUR website!I am 6 years older than my sister.How old will I be when I am 3 times older than she?
.
Let x = sister's age
then
x-6 = "my age"
.
3(x-6) = x
3x-18 = x
2x-18 = 0
2x = 18
x = 9 yrs (sister's age)
.
"my age":
x-6 = 9-6 = 3 years old (solution)
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Question 167906: Six years ago, Sam was three times as old as Sue. Four years from now Sam will be twice as old as Sue will be. Find the present age of each.: Six years ago, Sam was three times as old as Sue. Four years from now Sam will be twice as old as Sue will be. Find the present age of each.
Answer by ankor@dixie-net.com(4508) (Show Source):
You can put this solution on YOUR website!Let x = Sam's present age
Let y = Sue's present age
:
Write an equation for each statement:
"Six years ago, Sam was three times as old as Sue."
x - 6 = 3(y-6)
x - 6 = 3y - 18
x = 3y - 18 + 6
x = (3y - 12)
:
" Four years from now Sam will be twice as old as Sue will be."
x + 4 = 2(y+4)
x + 4 = 2y + 8
x = 2y + 8 - 4
x = 2y + 4
:
Find the present age of each.
:
From the 1st equation, replace x with (3y-12) in the above equation:
3y - 12 = 2y + 4
3y - 2y = 4 + 12
y = 16 yrs is Sue's present age
:
Find x using the the equation: x = 2y + 4
x = 2(16) + 4
x = 36 yrs is Sam's present age
:
:
Check solution in the statement:
"Six years ago, Sam was three times as old as Sue."
36 - 6 = 3(16-6)
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Question 167524: Lisa's age is 2/3 Leslie's age. Two years ago, Lisa's age was 1/2 of what Leslie's age will be in five years. How old is each girl now?: Lisa's age is 2/3 Leslie's age. Two years ago, Lisa's age was 1/2 of what Leslie's age will be in five years. How old is each girl now?
Answer by Mathtut(373) (Show Source):
You can put this solution on YOUR website!lets call leslie e and lisa i
i=2/3(e)........eq 1
(i-2)=1/2(e+5)..eq 2
substitute i's value from eq 1 into eq 2
2/3(e)-2=1/2(e)+5/2 multiply by 6
:
4e-12=3e+15
e=27
 leslie's age
 lisa's age
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Question 167500: {2x+y=16
{3(x+y)=5x
how do i make those equations as one age word problem?: {2x+y=16
{3(x+y)=5x
how do i make those equations as one age word problem?
Answer by Mathtut(373) (Show Source):
You can put this solution on YOUR website!the sum of two times Pauls age and Mike's age is 16 . Three times the sum of both of their ages is the same as five times Paul's age.
2x+y=16
{3(x+y)=5x
3x+3y=5x--->-2x+3y=0
add the 2 equations and the x terms are eliminated
so we have 4y=16---->y=4 so mike is 4
to find Pauls age plug into either equation.. 2x+4=16----->2x=12---->x=6 which would be pauls age
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Question 167468: Ben's age is four years less than three times that of his younger sister Amy. Half of Ben's age increased by Amy's age is 2 years more than twice Amy's age. Find their ages.: Ben's age is four years less than three times that of his younger sister Amy. Half of Ben's age increased by Amy's age is 2 years more than twice Amy's age. Find their ages.
Answer by ankor@dixie-net.com(4508) (Show Source):
You can put this solution on YOUR website!Let b = Ben's age now
Let a = Amy's age now
;
Write an equation for each statement:
:
"Ben's age is four years less than three times that of his younger sister Amy."
b = 3a - 4
:
" Half of Ben's age increased by Amy's age is 2 years more than twice Amy's age."
 b + a = 2a + 2
subtract a from both sides
b = 2a - a + 2
b = a + 2
Multiply both sides by 2 to get rid of the fraction
b = 2(a+2)
b = 2a + 4
:
Find their ages.
;
Substitute (3a-4) for b in the above equation
3a - 4 = 2a + 4
:
3a - 2a = 4 + 4
:
a = 8 yrs is Amy's age
:
Find b
b = 2a +4
b = 2(8) + 4
b = 20 yrs is Ben's age
:
:
Check solution in the statement:
" Half of Ben's age increased by Amy's age is 2 years more than twice Amy's age."
20 + 8 = 2(8) + 2
10 + 8 = 16 + 2
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Question 167371: Three exteenagers find the product of their ages is 26,390. Find the sum of their ages?: Three exteenagers find the product of their ages is 26,390. Find the sum of their ages?
Answer by Alan3354(1225) (Show Source):
You can put this solution on YOUR website!Three exteenagers find the product of their ages is 26,390. Find the sum of their ages?
-----------------
Since they're "exteenagers" they're all older than 19. The problem is to factor 26390 into 3 factors that are greater than 19.
There's only one 2 factor in 26390, so only one factor is an even number.
One approach is to factor it completely and the assemble 3 numbers greater than 19.
26390 = 2 x 5 x 7 x 13 x 29
29 is OK by itself, so make 2 numbers >19 out of the remaining 4.
2, 5, 7 and 13
2 times 5 or 7 is less than 20, so that's no good.
2*13 = 26 and 5*7 = 35 works, so it's:
26, 35 and 29
BTW, there's no algebraic solution to this problem. It's trial and error.
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Question 167167: Please help me answer this question:
Tom's father is 3 times old as Tom. 4 years ago, he was 4 times older. How old is Tom?: Please help me answer this question:
Tom's father is 3 times old as Tom. 4 years ago, he was 4 times older. How old is Tom?
Answer by ptaylor(1326) (Show Source):
You can put this solution on YOUR website!Let x=Tom's age now
Then 3x=Tom's father's age now
x-4=Tom's age 4 years ago
4(x-4)=Tom's father's age 4 years ago
So, our equation to solve is:
4(x-4)=3x-4 get rid of parens
4x-16=3x-4 subtract 4x from and add 4 to each side
4x-4x-16+4=3x-4x-4+4 collect like terms
-12=-x or
x=12 --------------Tom's age now
3x=3*12=36 Tom's father's age now
CK
4(12-4)=3*12-4
32=36-4
32=32
Hope this helps---ptaylor
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Question 167013: The sum of the ages of four daughters, Abigail, Bonnie, Cena, and Daphne, is 40. The difference between the ages of the youngest, Daphne, and the oldest, Abigail, is 6. The second born, Bonnie, is 2 years younger than the oldest, Abigail, and the third born, Cena, is the average of the ages of the youngest, Daphne, and the second born, Bonnie. How old is the father, who is 30 years older than the youngest daughter?: The sum of the ages of four daughters, Abigail, Bonnie, Cena, and Daphne, is 40. The difference between the ages of the youngest, Daphne, and the oldest, Abigail, is 6. The second born, Bonnie, is 2 years younger than the oldest, Abigail, and the third born, Cena, is the average of the ages of the youngest, Daphne, and the second born, Bonnie. How old is the father, who is 30 years older than the youngest daughter?
Answer by ankor@dixie-net.com(4508) (Show Source):
You can put this solution on YOUR website!Write an equation for each statement, we will try to get everything in terms of a
:
The sum of the ages of four daughters, Abigail, Bonnie, Cena, and Daphne, is 40.
a + b + c + d = 40
:
The difference between the ages of the youngest, Daphne, and the oldest, Abigail, is 6.
a - d = 6
-d = 6 - a
d = a - 6; multiplied equation by -1
:
The second born, Bonnie, is 2 years younger than the oldest, Abigail,
a - b = 2
-b = 2 - a
b = a - 2
:
third born, Cena, is the average of the ages of the youngest, Daphne, and the second born, Bonnie.
c = 
Substitute (a-2) for b and (a-6) for d
c =  = 
Cancel out the denominator and we have:
c = a - 4
:
Substitute for b, c, d in the first equation, find a:
a + (a-2) + (a-4) + (a-6) = 40
4a - 12 = 40
4a = 40 + 12
4a = 52
a = 
a = 13 yrs is Abigail's age
Then
b = 13 - 2
b = 11 yrs is Bonnie
and
c = 13 - 4
c = 9 yrs is Cena
and
d = 13 - 6
d = 7 yrs is Daphne
:
How old is the father, who is 30 years older than the youngest daughter?
Father = 7 + 30 = 37 yrs old
:
:
Check solution, find the total
13 + 11 + 9 + 7 = 40
:
A lot of steps but not that hard, right?
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Question 166964: What is the meaning of Age in word problems? and give examples: What is the meaning of Age in word problems? and give examples
Answer by midwood_trail(231) (Show Source):
You can put this solution on YOUR website!Age word problems are about the age(s) of people in the present, past or future.
How old is Tom? How old was Rita 3 years ago?
Here are two samples:
(1) In three more years, Miguel's grandfather will be six times as old as Miguel was last year. When Miguel's present age is added to his grandfather's present age, the total is 68. How old is each one now?
(2) One-half of Rita's age two years from now plus one-third of her age three years ago is twenty years. How old is she now?
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Question 166972: Anna made the following announcement:
" In 7 years, I will be half my mother's age. Thirteen years ago, she was 6 times as old as I was then."
How old is Anna now?
My teacher gives us a "problem of the week" every week and this is it. I'm not sure how to figure out the answer.: Anna made the following announcement:
" In 7 years, I will be half my mother's age. Thirteen years ago, she was 6 times as old as I was then."
How old is Anna now?
My teacher gives us a "problem of the week" every week and this is it. I'm not sure how to figure out the answer.
Answer by Alan3354(1225) (Show Source):
You can put this solution on YOUR website!Anna made the following announcement:
" In 7 years, I will be half my mother's age. Thirteen years ago, she was 6 times as old as I was then."
How old is Anna now?
--------------------
A = Anna's age
M = Mother's age
In 7 years, I will be half my mother's age.
M+7 = 2*(A+7)
--------------
Thirteen years ago, she was 6 times as old as I was then.
M-13 = 6*(A-13)
Now there are 2 eqns in 2 unknowns.
M + 7 = 2A+14 eqn 1
M -13 = 6A-78 eqn 2
3M+21 = 6A+42 eqn 1 times 3
Subtract
-2M-34= -120
-2M = -86
M = 43 (Mother's age)
Sub into eqn 1
43+7 = 2A + 14
2A = 36
A = 18 (Anna's age)
-----------
Check:
13 years ago, they were ages 5 and 30, = 6 times.
In 7 years, they'll be 25 and 50, 2 times.
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Question 166952This question is from textbook
: Cassidy is 3 times as old as Drew. In 8 years, Cassidy will only be twice as old as Drew. How old is cassidy right now?This question is from textbook
: Cassidy is 3 times as old as Drew. In 8 years, Cassidy will only be twice as old as Drew. How old is cassidy right now?
Answer by nerdybill(1052) (Show Source):
You can put this solution on YOUR website! Cassidy is 3 times as old as Drew. In 8 years, Cassidy will only be twice as old as Drew. How old is cassidy right now?
.
Let x = Drew's age
then
3x = Cassidy's age
.
3x+8 = 2(x+8)
3x+8 = 2x+16
x+8 = 16
x = 8 years
.
Cassidy is 8 years old
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Question 166624: If Leah is 6 years older than her sister, Sue, and John is 5 years older than Leah, and the total of their ages is 41. Then how old is Sue? : If Leah is 6 years older than her sister, Sue, and John is 5 years older than Leah, and the total of their ages is 41. Then how old is Sue?
Answer by nerdybill(1052) (Show Source):
You can put this solution on YOUR website! If Leah is 6 years older than her sister, Sue, and John is 5 years older than Leah, and the total of their ages is 41. Then how old is Sue?
.
Let x = Sue's age
then
x+6 = Leah's age
x+6+5 = John's age
.
x + x+6 + x+6+5 = 41
3x + 17 = 41
3x = 24
x = 8 years (Sue's age)
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Question 166440: The equation V = -2000t + 20,000 describes the value in dollars of a certain model of car after it is t years old. If a car is worth $12,000, substitute 12,000 into the equation to find the age of the car.
o 3 years
o 4 years
o 5 years
o 6 years: The equation V = -2000t + 20,000 describes the value in dollars of a certain model of car after it is t years old. If a car is worth $12,000, substitute 12,000 into the equation to find the age of the car.
o 3 years
o 4 years
o 5 years
o 6 years
Answer by Mathtut(373) (Show Source): |
Question 166257: Please held me solve this problem:
Mark is 11 years older that his sister. In 8 years he will be twice as old as she will be then. How old are they now?
: Please held me solve this problem:
Mark is 11 years older that his sister. In 8 years he will be twice as old as she will be then. How old are they now?
Answer by checkley77(3423) (Show Source):
You can put this solution on YOUR website!M=S+11
M+8=2(S+8)
(S+11)+8=2(S+8)
S+19=2S+16
S-2S=16-19
-S=-3
S=3 YEARS OLD FOR THE SISTER NOW.
M=3+11=14 YEARS OLD FOR MARK NOW.
PROOF:
14+8=2(3+8)
22=2*11
22=22
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Question 166257: Please held me solve this problem:
Mark is 11 years older that his sister. In 8 years he will be twice as old as she will be then. How old are they now?
: Please held me solve this problem:
Mark is 11 years older that his sister. In 8 years he will be twice as old as she will be then. How old are they now?
Answer by stanbon(18792) (Show Source):
You can put this solution on YOUR website!Please held me solve this problem:
Mark is 11 years older that his sister. In 8 years he will be twice as old as she will be then. How old are they now?
------------------
Ages NOW:
Sister's age is "x"
Mark's age is "x+11"
------------------------
Ages in 8 years:
Sister will be "x+8"
Mark will be "x+19"
------------------------
EQUATION:
x+19 = 2(x+8)
x+19 = 2x+16
x = 3
---------
Sister is NOW 3 years old
Mark is NOW 14 years old
===========================
Cheers,
Stan H.
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Question 166037: The two taylor girls were born in consecutive, even years. If the product of their age is 224, how old is each girl?: The two taylor girls were born in consecutive, even years. If the product of their age is 224, how old is each girl?
Answer by checkley77(3423) (Show Source): |
Question 166050: The sum od Dylan's and Krista's ages is 25. In 12 years, Dylan will be seven years older than four times as old as Krista was five years ago. How old are Dylan and Krista now?: The sum od Dylan's and Krista's ages is 25. In 12 years, Dylan will be seven years older than four times as old as Krista was five years ago. How old are Dylan and Krista now?
Answer by Mathtut(373) (Show Source):
You can put this solution on YOUR website!call Dylan=d
: Krista=k
so  and 
:  and  simplifying
:  substituting d value in first equation into 2nd equation
:  combining terms  divide by 5 
now 
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Question 165863: Fifteen years ago a man was two-thirds as old as he will be in 12 years. How old is he now?: Fifteen years ago a man was two-thirds as old as he will be in 12 years. How old is he now?
Answer by ankor@dixie-net.com(4508) (Show Source):
You can put this solution on YOUR website!Fifteen years ago a man was two-thirds as old as he will be in 12 years.
How old is he now? It's x
:
x - 15 =  (x+12)
:
Multiply both sides by 3 to get rid of the annoying demominator
3(x-15) = 3* (x+12)
:
3x - 45 = 2(x+12)
:
3x - 45 = 2x + 24
:
3x - 2x = 24 + 45
:
x = 69 yrs now, an old guy like me!
:
:
Check solution in the statement:
"Fifteen years ago a man was two-thirds as old as he will be in 12 years."
69 - 15 = (69 + 12)
54 = *81
54 = 54
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Question 165862: John is 4 years older than his sister and 6 years ago he was twice his sister's age then. How old is each now?: John is 4 years older than his sister and 6 years ago he was twice his sister's age then. How old is each now?
Answer by ankor@dixie-net.com(4508) (Show Source):
You can put this solution on YOUR website!Let j = John's age now
let s = sister's age now
:
Write an equation for each statement:
:
"John is 4 years older than his sister"
j = s + 4
:
"6 years ago he was twice his sister's age then."
(j-6) = 2(s-6)
j - 6 = 2s - 12
j = 2s - 12 + 6
j = 2s - 6
:
How old is each now?
:
From the 1st equation, substitute (s+4) for j in the last equation
s + 4 = 2s - 6
4 + 6 = 2s - s
10 = s (sister's age now)
then
10 + 4 = 14 yr John's age now
:
:
Check solution in the statement:
"6 years ago he was twice his sister's age then."
14 - 6 = 2(10 - 6)
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Question 165932: Paul is 3 years younger than his friend Peter.In seven years, the product of their ages will be five more than the product of their ages five years ago. How old are they now?: Paul is 3 years younger than his friend Peter.In seven years, the product of their ages will be five more than the product of their ages five years ago. How old are they now?
Answer by Mathtut(373) (Show Source):
You can put this solution on YOUR website!This problem is impossible. There is no way that the difference between ages multiplied 7years from now, and 5 years ago, can be only 5 years. this problem needs to be re written in my opinion.
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Question 165896: Fred is 3 yrs. older than his sister Mary. In 7 yrs she will be 6/7 of his age. How old are they? : Fred is 3 yrs. older than his sister Mary. In 7 yrs she will be 6/7 of his age. How old are they?
Answer by midwood_trail(231) (Show Source):
You can put this solution on YOUR website!Fred is 3 years older than his sister Mary. In 7 yrs she will be 6/7 of his age. How old are they?
Mary's age now = x
Fred's age now = x + 3
In seven years each person will be 7 years older, right?
Here's how we represent that:
Mary = x + 7
Fred = (x + 3) + 7
We now multiply (6/7) times Fred's age 7 years form now.
The equation looks like this:
x + 7 = (6/7)(x + 3) + 7
We multiply every term by 7 (our LCD).
Doing so, we get this:
7x + 49 = 6x + 18 + 49
We now combine like terms:
7x - 6x = -49 + 67
x = 18
Mary is 18 years old.
Fred is 18 + 3 = 21 years old.
Did you follow?
|
Question 165752This question is from textbook
: A mother is five times as old as her son. If twice the age of the son is 3 years less than half of the age of the mother, how old are they.
I need help setting this problem up, for some reason I can not figure this out.This question is from textbook
: A mother is five times as old as her son. If twice the age of the son is 3 years less than half of the age of the mother, how old are they.
I need help setting this problem up, for some reason I can not figure this out.
Answer by Mathtut(373) (Show Source):
You can put this solution on YOUR website!lets call m=mother and s=son so m=5s because she is 5time older
and 2s=1/2m-3 so taking the value for m in the 1st equation and substituting it into the 2nd we get 2s=1/2(5s)-3 so 2s=5/2s-3 subtract 2s and add 3 to both sides and you get 1/2s=3 multiply both sides by 2 and you get s=6 now plug in the s value into m=5s and we get m=5(6) so m=30
son is 6 and mother is 30
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Question 146358: Write an equation which models how old, in years, you will be when you are 3 times as old as the younger person.
Age now (mother) = 35
Younger person (daughter) age now = 14
age difference = 21 years
mother = X + 21
daughter = X
I was thinking it should be 3x + 21 = 3X.
It's not coming out right. Please help.: Write an equation which models how old, in years, you will be when you are 3 times as old as the younger person.
Age now (mother) = 35
Younger person (daughter) age now = 14
age difference = 21 years
mother = X + 21
daughter = X
I was thinking it should be 3x + 21 = 3X.
It's not coming out right. Please help.
Answer by Fombitz(1744) (Show Source):
You can put this solution on YOUR website!Mother = M = 35
Daughter = D = 14
In x years, the mother will be,
In x years, the daughter will be,
When will the mother be 3 times the daughters age?
3 1/2 years ago, the mother was 3 times the daughter's age.
The mother was 31 1/2 years old.
The daughter was 10 1/2 years old.
Are you sure the mother and daughter ages are correct??
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Question 165703: A man is now 42 years old and his friend is 33 years old. How many years ago was the man twice as old as his friend was then?: A man is now 42 years old and his friend is 33 years old. How many years ago was the man twice as old as his friend was then?
Answer by Fombitz(1744) (Show Source): |
Question 165258: difference between the ages of two cousins is 4 years. if the sum of thier ages is 42 years. how can i found their ages?
thank you: difference between the ages of two cousins is 4 years. if the sum of thier ages is 42 years. how can i found their ages?
thank you
Answer by stanbon(18792) (Show Source):
You can put this solution on YOUR website!difference between the ages of two cousins is 4 years. if the sum of thier ages is 42 years. how can i found their ages?
--------------------------------------
One cousin is "x" years old; the other is x+4 years old.
--------------
EQUATION:
x + (x+4) = 42
2x = 38
x = 19 yrs old (one of the cousins)
x+4 = 23 yrs old (the other cousin)
========================================
Cheers,
Stan H.
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Question 165127: the sum of the ages of two sister's is 37.the difference between four times the older sister's and three times the younger sister's age is 43.find the age of each sister.: the sum of the ages of two sister's is 37.the difference between four times the older sister's and three times the younger sister's age is 43.find the age of each sister.
Answer by nerdybill(1052) (Show Source):
You can put this solution on YOUR website!Let x = younger sister's age
and y = older sister's age
.
Since we have two unknowns, we'll need two equations.
.
Equation 1: "the sum of the ages of two sister's is 37"
x+y = 37
.
Equation 2: "the difference between four times the older sister's and three times the younger sister's age is 43"
4y - 3x = 43
.
Using the substitution method, solve equation 1 for y:
x+y = 37
y = 37-x
.
Substitute the above into equation 2 and solve for x:
4y - 3x = 43
4(37-x) - 3x = 43
148 - 4x - 3x = 43
148 - 7x = 43
148 = 7x+43
105 = 7x
15 years = x (younger sister's age)
.
Older sister's age, if found by plugging the above into equation 1 and solving for y:
x+y = 37
15+y = 37
y = 22 years (older sister's age)
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Question 165126: A woman id three times as old as her son,and the sum of their ages id 52.find each person's age.: A woman id three times as old as her son,and the sum of their ages id 52.find each person's age.
Answer by nerdybill(1052) (Show Source):
You can put this solution on YOUR website!Let x = son's age
then because "woman is three times as old as her son"
3x = woman's age
.
From:"sum of their ages id 52" we get
x + 3x = 52
4x = 52
x = 13 years (son's age)
.
woman's age:
3x = 3(13) = 39 years (mother's age)
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Question 131579: Mr ree is 4 years older than ms ree, but their actual ages are a mystery, if they tell you that the summ of the squares of their ages is 3706, how old are they?: Mr ree is 4 years older than ms ree, but their actual ages are a mystery, if they tell you that the summ of the squares of their ages is 3706, how old are they?
Answer by nerdybill(1052) (Show Source):
You can put this solution on YOUR website!Let x = Ms Ree's age
then because "Mr ree is 4 years older than ms ree"
x+4 = Mr Ree's age
.
From: "the sum of the squares of their ages is 3706"
x^2 + (x+4)^2 = 3706
x^2 + x^2+8x+16 = 3706
2x^2+8x+16 = 3706
2x^2+8x-3690 = 0
x^2+4x-1845 = 0
.
Factoring:
(x-41)(x+45) = 0
x = {41, -45}
.
We can toss out the negative answer so:
x = 41 (Ms Ree's age)
.
Mr. Ree's age:
x+4 = 41+4 = 45 years (Mr. Ree's age)
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Question 165145: A woman id three times as old as her son,and the sum of their ages id 52.find each person's age.: A woman id three times as old as her son,and the sum of their ages id 52.find each person's age.
Answer by nerdybill(1052) (Show Source):
You can put this solution on YOUR website! A woman id three times as old as her son,and the sum of their ages id 52.find each person's age.
.
Let x = son's age
then because "woman is three times as old as her son"
3x = woman's age
.
From:"sum of their ages id 52" we get
x + 3x = 52
4x = 52
x = 13 years (son's age)
.
woman's age:
3x = 3(13) = 39 years (mother's age)
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Question 165115: A woman is three times as old as her son,and the sum of their ages id 52.find each person's age.: A woman is three times as old as her son,and the sum of their ages id 52.find each person's age.
Answer by edjones(2391) (Show Source): |
Question 165032: 1. A man is now 42 years old and his friend is 33 years old. How many years ago was the man twice as old as his friend was then?
2. Paul is 3 years younger than his friend Peter. In seven years the product of their ages will be five more than the product of their ages 5 years ago. How old are they now?
please answer this.. I really need this
: 1. A man is now 42 years old and his friend is 33 years old. How many years ago was the man twice as old as his friend was then?
2. Paul is 3 years younger than his friend Peter. In seven years the product of their ages will be five more than the product of their ages 5 years ago. How old are they now?
please answer this.. I really need this
Answer by Mathtut(373) (Show Source):
You can put this solution on YOUR website!1. They kind of through a curve ball on this problem... lets call the number of years ago x. and the man we will call A and the friend B. so this is how we write the equation (A-x)=2(B-x) we know that A=42 and B=33 so plug in
42-x=2(33-x) simplify 42-x=66-2x x=24 so the answer is 24 years ago
2.Another curve... something seems to be wrong in the second question: to multiply two ages together in seven years from today as opposed to muliplying those ages 5 years ago and those products only have a difference of 5 is not possible imo
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Question 165032: 1. A man is now 42 years old and his friend is 33 years old. How many years ago was the man twice as old as his friend was then?
2. Paul is 3 years younger than his friend Peter. In seven years the product of their ages will be five more than the product of their ages 5 years ago. How old are they now?
please answer this.. I really need this
: 1. A man is now 42 years old and his friend is 33 years old. How many years ago was the man twice as old as his friend was then?
2. Paul is 3 years younger than his friend Peter. In seven years the product of their ages will be five more than the product of their ages 5 years ago. How old are they now?
please answer this.. I really need this
Answer by ankor@dixie-net.com(4508) (Show Source):
You can put this solution on YOUR website!I want to do more than answer it, I want to show you how to do it.
:
A man is now 42 years old and his friend is 33 years old. How many years ago was the man twice as old as his friend was then?
:
Let t = number of yrs for this to be true
:
Subtract t from both sides and make an equation:
:
Man, t yrs ago, was twice as old, as his friend t yrs ago
42 - t = 2(33 - t)
42 - t = 66 - 2t; multiply what's inside the brackets
Some basic algebra operations
+2t - t = 66 - 42
t = 24 yrs ago
:
We can prove this
42 - 24 = 18;
33 - 24 = 9
:
:
2. Paul is 3 years younger than his friend Peter. In seven years the product of their ages will be five more than the product of their ages 5 years ago. How old are they now?
:
This problem is impossible, there is no way that the product 7 yrs from now
will be only 5 more than the product 5 yrs ago
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Question 164986: In two years time, Karishma's age will be three times Emily's age.
Emily is now t years old.
How old is Karishma now?
(A) 3t (B) 3t + 2 (C) 3t + 4 (D) 3t + 5: In two years time, Karishma's age will be three times Emily's age.
Emily is now t years old.
How old is Karishma now?
(A) 3t (B) 3t + 2 (C) 3t + 4 (D) 3t + 5
Answer by midwood_trail(231) (Show Source):
You can put this solution on YOUR website!In two years time, Karishma's age will be three times Emily's age.
Emily is now t years old. How old is Karishma now?
(A) 3t (B) 3t + 2 (C) 3t + 4 (D) 3t + 5
Here is my second try.
K = 3(t + 2) - 2
K = 3t + 6 - 2
K = 3t + 4
Choice C
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Question 164791: rizza's age is one year more than twice norries's age. eight years ago, the sum of their ages was equal to rizza's age ten years from now. how old are they?: rizza's age is one year more than twice norries's age. eight years ago, the sum of their ages was equal to rizza's age ten years from now. how old are they?
Answer by ankor@dixie-net.com(4508) (Show Source):
You can put this solution on YOUR website!Let r = R's age now
Let n = N's age now
:
Write an equation for each statement;
:
"rizza's age is one year more than twice norries's age."
r = 2n + 1
:
" eight years ago, the sum of their ages was equal to rizza's age ten years from now."
(r-8)+(n-8) = r + 10
:
r + n - 16 = r + 10
:
r - r + n = 10 + 16
:
n = 26 yrs is N's age now
":
we know r = 2n + 1
r = 2(26) + 1
r = 53 yrs is R's age
:
:
See how those solution work in the statement
"eight years ago, the sum of their ages was equal to rizza's age ten years from now."
(53-8) + (26-8) = 53 + 10
45 + 18 = 63; confirms our solutions
how old are they?
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Question 164053: A company's assets have a value of $30,000 at the beginning of the year 1999. By the beginning og 2001 the assets has depreciated to $26,000.
1) Assuming that the depreciation is linear, write the linear equation rating the value V of the assest in terms of the years passed since the beginning of 1999.
2)Find the value of the asest in the year 2006
3)Find after how many years the value of the asset will be $7,000.
4)Find after how many years wil the asset be worthless(value=0): A company's assets have a value of $30,000 at the beginning of the year 1999. By the beginning og 2001 the assets has depreciated to $26,000.
1) Assuming that the depreciation is linear, write the linear equation rating the value V of the assest in terms of the years passed since the beginning of 1999.
2)Find the value of the asest in the year 2006
3)Find after how many years the value of the asset will be $7,000.
4)Find after how many years wil the asset be worthless(value=0)
Answer by MRperkins(77) (Show Source):
You can put this solution on YOUR website!ok, the first thing we need is to find the formula:
The problem says that the formula is linear so let's use the slope-intercept form or y=mx+b where m=slope and b=the y-intercept.
Remember that the slope is simply how much y changes for each unit of x. So in this situation when x moves from 1999 to 2001 the y changes from 30,000 to 26,000.
Formula: slope=(change in y)/(change in x)
or
or
So in this case x changed 2 and y changed -4,000, so to find out the change per year instead of per 2 years: divide -4000 by 2 and you get the change in y divided by the change in x or -2000
now we know that y=-2000x+b
the y-intercept or "b" is the y value when x=0 and x is the number of years passed since the beginning of 1999 so when x=0 y=30,000
therefore our formula is 
Part 2
Find the value of the asset in the year 2006:
2006-1999=7
so find the value of y when x=7
y=-2000(7)+30000
y=-14000+30000
y=16000
Part 3
Find after how many years the value of the asset will be $7,000.
let y=7000 and solve for x
7000=-2000x+30000
subtract 30000 from each side
-23000=-2000x
divide each side by -2000
11.5=x
so the value of assets will be $7000 after 11.5 years
Part 4
Find after how many years wil the asset be worthless(value=0)
let y=0 and solve for x
0=-2000x+30000
subtract 30000 from both sides
-30000=-2000x
divide each side by -2000
15=x
so the value of assets will be worthless after 15 years
.
.
I hope this helps
PayPal donations accepted through justin.sheppard.tech@hotmail.com
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Question 164851: The legs of a right triangle differ by 2 cm. and the hypotenuse is 4 cm. more than the shorter leg. Find the sides of the triangle?: The legs of a right triangle differ by 2 cm. and the hypotenuse is 4 cm. more than the shorter leg. Find the sides of the triangle?
Answer by MRperkins(77) (Show Source):
You can put this solution on YOUR website!To understand this problem first draw a representation of a right triangle. Label one leg x and the other leg x-2.
Given: the hypotenuse is 4 cm. more than the shorter leg so:
label the hypotenuse x-2+4 or x+2
Now use the Pythagorean Theorem to find the value of x
or
Order of operations says we have to multiply where possible so use the FOIL method.
combine like terms:
Move everything to the same side.
Subtract x^2 from both sides and you get:
Subtract 4x from both sides and you get:
x^2-8x+4=4
Subtract 4 from both sides and you get:
x^2-8x=0
Factor out an x and you get:
x(x-8)=0
This statement is true when x=0 or (x-8)=0
x-8=0
add 8 to both sides and you get
x=8
x=0;x=8 However, because we are dealing with a length of a triangle x cannot=0
Therefore x=8 is the only answer to this problem.
Check your work!
your sides are 8;8-2;8-2+4 or 8;6;10
we know that 
or
64+46=100
or
100=100 and therefore the answer checks out to be true.
Remember that you must always try to find a unit label for every answer. In this case it is centimeters so your final answer is 6 cm; 8 cm; and 10 cm
.
.
Paypal donations accepted through justin.sheppard.tech@hotmail.com
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Question 164841: the difference between the ages of two students is 4 years. if the sum of their ages is 425 years. find each students age: the difference between the ages of two students is 4 years. if the sum of their ages is 425 years. find each students age
Answer by Mathtut(373) (Show Source):
You can put this solution on YOUR website!students a and b. so a-b=4 and a+b=425 solve for a in first equation and you get a=b+4 substitute that into 2nd equation we get (b+4)+b=425 solve for b b= 210.5 so a =214.5......now that is some old students were these bible time students???? lol
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Question 164811: the sum of the ages of two sisters is 37. the difference between four times the older sisters's age and three times the younger sistter's age is 43. how can i find the age of these sisters?: the sum of the ages of two sisters is 37. the difference between four times the older sisters's age and three times the younger sistter's age is 43. how can i find the age of these sisters?
Answer by Mathtut(373) (Show Source):
You can put this solution on YOUR website!lets call the younger sister s1 and the older sister s2. now we know that s1+s2=37 and we know that difference between 4 times the older sisters age which we will write as 4s2 and 3 times the younger sister age which we will write as 3s1 equals 43..writing this out this would be 4s2-3s1=43. So solving for s1 in the 1st equation we get s1=37-s2 plugging that into the second equation we get
4s2-3(37-s2)=43. now multiply out and simplify...we get 7s2=154 divide by 7 and s2=22 so since s1=37-s2(22) we get s1 is 15
answers younger sister 15
older sister 22
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Question 164804: rizza's age is one year more than twice norrie"s ge. eight years ago, the sum of thier ages was equal to rizza's age ten years from now. how old are they now?: rizza's age is one year more than twice norrie"s ge. eight years ago, the sum of thier ages was equal to rizza's age ten years from now. how old are they now?
Answer by Mathtut(373) (Show Source):
You can put this solution on YOUR website!ok equations to work with. first R(rizzas age)= 2 N(norries age)+1
now eight years ago the sum of their ages so lets write that as (R-8)+ (N-8)
= to rizzas age 10 years from now written as R+10
so we have R=2N+1 and R-8+N-8=R+10 substituting R=2N+1 into the 2nd equation we have (2N+1)-8+N-8=(2N+1)+10 solving for N we arrive at N=26 now plugging this value into R=2N+1 we arrive at R=53
so Rizzas age was 53 and Norries was 26
checking for eight years ago we have Rizza at 45 and Norrie at 18 add those 2 numbers together and you get 63 which is 10 years older than Rizza's age at this time.
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Question 164651: The sum of Wilbur’s age and Fred’s age is 20 years.
Wilbur’s age 1 year from now will be 9 times Fred’s age 1 year ago.
Find the present age of Wilbur and Fred.: The sum of Wilbur’s age and Fred’s age is 20 years.
Wilbur’s age 1 year from now will be 9 times Fred’s age 1 year ago.
Find the present age of Wilbur and Fred.
Answer by jojo14344(833) (Show Source):
You can put this solution on YOUR website!
1st condition:  , EQN 1
Also we get via EQN 1:  , EQN 2
2nd condition:
Wilbur's Age One year from now, so  ---> will be 9 times as Fred's age a year ago,  right?
Putting into eqn the 2 ages via condition 2:
 , EQN 3
Subst. EQN 2 in EQN 3:
 -----> 
 , Fred's Age now
Via EQN 2
 , Wilbur's Age now
You can check by going to EQN 3, but it's nice going to condition 2 (it's the same anyway):
Wilbur's Age one year from now, 17+1=18yrs, will be 9 times as Fred's age a year ago,  .See highlighted, is 9 times as Wilbur's age, (9*2=18yrs).
Thank you,
Jojo
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