SOLUTION: Find a pair of numbers (x,y) so that expression x^2 + y^2 - 2x gives as small a value as possible.

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Question 387632: Find a pair of numbers (x,y) so that expression x^2 + y^2 - 2x gives as small a value as possible.
Found 2 solutions by edjones, robertb:
Answer by edjones(8007) About Me  (Show Source):
You can put this solution on YOUR website!
x^2 + y^2 - 2x
any number greater than or less than zero for y will make y^2 greater than zero so y must be zero.
x^2-2x has a minimum at -b/2a
-(-2)/2 = 1
(1,0) Answer
x^2 + y^2 - 2x = -1 at (1,0)
.
Ed

Answer by robertb(5830) About Me  (Show Source):
You can put this solution on YOUR website!
x%5E2+%2B+y%5E2+-+2x+=+x%5E2+%2B+y%5E2+-+2x+%2B+1+-+1+=+%28x+-+1%29%5E2+%2B+y%5E2+-+1. Now %28x+-+1%29%5E2+%2B+y%5E2 is smallest when x = 1 and y = 0 (where the value of the expression is -1). (1,0) is the ordered pair.