SOLUTION: sketch the graph of {{{y=(1+x)^2(2-x)}}}

Question 286355: sketch the graph of
Answer by texttutoring(324) (Show Source): You can put this solution on YOUR website!
All you really need to know is where the roots of the equation are, and what the shape of the curve is.
First, we set y=0:

So, either: or
x=-1,x=-1. There is a double root at x= -1.
if 2-x=0, then x=2. There is a single root at x=2.
Either one can be true because any number multiplied by zero is zero.
This is a negative cubic (because of the 2-x term). which means it starts in Quadrant 4 (the bottom-right) and moves up and left, to Quadrant 2 (top-left). It crosses the x-axis once at x=2, and then it comes down to touch the x-axis at x=2.
I don't know how to post an image in here, so if you want to see a sketch of it, send me a message.
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