SOLUTION: A 5 pound bag of grass seed covers 9,000 square feet. How many pounds would be needed to cover 32,000 square feet?

Question 1200612: A 5 pound bag of grass seed covers 9,000 square feet. How many pounds would be needed to cover 32,000 square feet?
Found 3 solutions by ikleyn, greenestamps, MathTherapy:
Answer by ikleyn(52915)   (Show Source): You can put this solution on YOUR website!
.

Write a proportion as you read the problem = . From the proportion, find x = = = = 17 = 17.78 pounds (rounded). ANSWER

Solved.

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For introductory lessons on proportions, see the lessons
    - Proportions
    - Using proportions to solve word problems
    - Typical problems on proportions
    - Using proportions to estimate the number of fish in a lake
    - HOW TO algebraize and solve these problems using proportions
in this site.

Learn the entire subject from there.

Happy learning ( ! )

Answer by greenestamps(13216)   (Show Source): You can put this solution on YOUR website!

The response from the other tutor shows a typical very formal solution using a proportion. That of course is one way to set up and solve the problem.

For a more informal solution, using logical reasoning, you can simply say that since the area increased by a factor of 32,000/9,000 = 32/9, the amount of grass seed required will increase by a factor of 32/9.

ANSWER: 160/9 pounds, or 17.78 pounds (rounded)

You end up doing exactly the same calculation -- but the setup is faster and easier.

Answer by MathTherapy(10557)   (Show Source): You can put this solution on YOUR website!

A 5 pound bag of grass seed covers 9,000 square feet. How many pounds would be needed to cover 32,000 square feet? With A being the amount needed to cover the 32,000 sq ft, set up a proportion, as follows: ------ Simplifying right-side fraction 9A = 5(32) ---- Cross-multiplying Amount needed to cover the 32,000 sq ft, or

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