SOLUTION: A hair breaks under a tension of 1.1 N. What is the diameter of the hair? The tensile strength is 2.0 ✕ 10^8 Pa.

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Question 1161861: A hair breaks under a tension of 1.1 N. What is the diameter of the hair? The tensile strength is 2.0 ✕ 10^8 Pa.
Found 2 solutions by solver91311, ikleyn:
Answer by solver91311(24713)   (Show Source): You can put this solution on YOUR website!


You asked a Physics question. This is a Mathematics homework help site. Do you go to the Auto Parts store to buy vegetables?


John

My calculator said it, I believe it, that settles it
Answer by ikleyn(52786)   (Show Source): You can put this solution on YOUR website!
.

1 Pa = 1 N / 1 m^2.


If d is the diameter of the hair, then


   . = 1.1 N


which implies


     =  = . m^2 =  m^2.


Hence,


    d =  =  meters = 0.084 mm.    ANSWER

Solved.

It is very easy. Having a bit of common sense is just enough.



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