SOLUTION: Need help evaluating this expression.
tan(90 - ⊖) *tan(⊖)*sec(⊖)
A.) {{{ 1 }}}
B.) {{{ 2 }}}
C.) sec{⊖)
D.) cot(⊖)
Thanks.
Algebra.Com
Question 1059154: Need help evaluating this expression.
tan(90 - ⊖) *tan(⊖)*sec(⊖)
A.)
B.)
C.) sec{⊖)
D.) cot(⊖)
Thanks.
Answer by solve_for_x(190) (Show Source): You can put this solution on YOUR website!
Since tan(x) = sin(x) / cos(x), and sin(90 - x) = cos(x), and cos(90 - x) = sin(x), the
first term of the expression can be rewritten as:
tan(90 - ⊖) = sin(90 - ⊖)/cos(90 - ⊖) = cos(⊖)/sin(⊖)
Substituting this in place of tan(90 - ⊖) then gives:
=
= sec(⊖)
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