SOLUTION: In a city there are 15000 families. (3.5)% read news paper 'A' but not 'B' look into advertisements, 25% read news paper 'B' but not 'A' look into advertisements, 50% read both and
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Question 870270: In a city there are 15000 families. (3.5)% read news paper 'A' but not 'B' look into advertisements, 25% read news paper 'B' but not 'A' look into advertisements, 50% read both and look into advertisements. It is known that 8000 families read 'A', 4000 read 'B', and 1000 read both A and B then,
i) The number of families look into advertisements is ?,
ii). The no. of families who read at most one news paper is?.
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
It is unclear if the 3.5%, 25% and 50% are of the 15000 families of those who read
3.5% of those who read A , 25% of those who read B and 50% of those who read both
280+500+100=880 who read ads if the second choice
525+7500+3750=11775 if the first.
if 1000 read both then at most 11000 read just one.
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