SOLUTION: Let U = {4, 5, 6, 7, 8, 9, 10}, A = {4, 5, 6, 7}, B = {4, 5, 8, 9}, and C = {6, 8, 10}. List all the members of the given set. (Enter your answers as a comma-separated list.) (A &

Algebra.Com
Question 828728: Let U = {4, 5, 6, 7, 8, 9, 10}, A = {4, 5, 6, 7}, B = {4, 5, 8, 9}, and C = {6, 8, 10}. List all the members of the given set. (Enter your answers as a comma-separated list.)
(A ∪ B) ∩ C

Answer by jim_thompson5910(35256)   (Show Source): You can put this solution on YOUR website!
A ∪ B is the set of the combination of sets A and B. You basically combine them together and toss the duplicates. So,

A ∪ B = {4, 5, 6, 7, 4, 5, 8, 9} ... combine the two sets

A ∪ B = {4, 5, 6, 7, 8, 9} ... but remember to toss the duplicates (tossed 4,5)

-------------------------------------------------------

Now we must look at what the two sets A ∪ B = {4, 5, 6, 7, 8, 9} and C = {6, 8, 10} have in common. The numbers 6,8 are the only two numbers in BOTH sets.


So this is why the final answer is {6,8}

(A ∪ B) ∩ C = {6,8}

RELATED QUESTIONS

Let U = {4, 5, 6, 7, 8, 9, 10}, A = {4, 5, 6, 7}, B = {4, 5, 8, 9}, and C = {6, 8, 10}.... (answered by Fombitz)
Perform the given set operation. Let U = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}. (Enter your... (answered by Fombitz)
Let U = {5, 6, 7, 8, 9, 10, 11}, and A = {5, 6, 7, 8}. List all the members of the given... (answered by Fombitz)
Let U= {1, 2, 3, 4, 5, 6, 7, 8, 9, 10} A= {1, 2, 4, 6} B= {3, 7} C={1, 3, 6, 7, 8}... (answered by MathLover1)
Let U = {3, 4, 5, 6, 7, 8, 9}, A = {3, 4, 5, 6}, B = {3, 4, 7, 8}, and C = {5, 7, 9}.... (answered by ewatrrr)
Let U = {3, 4, 5, 6, 7, 8, 9}, A = {3, 4, 5, 6}, B = {3, 4, 7, 8}, and C = {5, 7, 9}.... (answered by MathLover1)
Let U = {5, 6, 7, 8, 9, 10, 11}, A = {5, 6, 7, 8}, B = {5, 6, 9, 10}, and C = {7, 9, 11}. (answered by ramkikk66)
Let U = {5, 6, 7, 8, 9, 10, 11}, A = {5, 6, 7, 8}, B = {5, 6, 9, 10}, and C = {7, 9, 11}. (answered by ewatrrr)
Let U = {5, 6, 7, 8, 9, 10, 11}, A = {5, 6, 7, 8}, B = {5, 6, 9, 10}, and C = {7, 9, 11}. (answered by richwmiller)