SOLUTION: {{{ for which value satisfies the equation 10*a^2-b^2=1 when a is greater 40 and b is greater than 100}}}

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Question 750058:
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For which value satisfies the equation when a is greater 40 and b is greater than 100?
:
Rearrange to
10a^2 = b^2 + 1
a^2 =
:
a =
let a > 40
> 40
Square both sides
> 1600
b^2 + 1 > 1600 * 10
b^2 > 16000-1
b >
b = 127
Find a
10a^2 = b^2 + 1
10a^2 = 127^2 + 1
10a^2 = 16129 + 1
a^2 = 16130/10
a^2 = 1613
a =
a = 40.162

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