SOLUTION: I invested 50 000 more in teachers' cooperation than in home owners' cooperative. If my total investments in the two cooperatives is 110 000, how much is my investment in each?

Question 612378: I invested 50 000 more in teachers' cooperation than in home owners' cooperative. If my total investments in the two cooperatives is 110 000, how much is my investment in each?
Answer by bucky(2189) (Show Source): You can put this solution on YOUR website!
Let x represent the unknown amount invested in the home owners' cooperative.
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Since 50 000 more is invested in the teachers' cooperative, we can write that the investment in the teachers' cooperative is x + 50 000
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The sum of these two investments is:
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x + x + 50 000 and adding the two x terms results in a total of 2x + 50 000
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But the problem tells you that the sum of the two investments is 110 000. Therefore, we can write the equation:
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2x + 50 000 = 110 000
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To solve this for x we can first eliminate the 50 000 on the left side by subtracting 50 000 from both sides to get:
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2x = 60 000
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Now we can solve for x by dividing both sides of this equation by 2 to get:
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x = 30 000
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Since we chose x to represent the amount invested in the home owners' cooperative, we know that we have 30 000 in it. And since 50 000 more was invested in the teachers' cooperative we know that we have invested 30 000 plus 50 000 for a total of 80 000 in the teachers cooperative.
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And as a check, the total of 30 000 in the home owners' cooperative plus the 80 000 in the teachers' cooperative does add up to the total 110 000 that we have invested all together.
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I hope this helps you to understand the problem and how you can solve it.
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