SOLUTION: In a class of 50 students, 24 like football, 21 basketball and 18 cricket. Six like football and basketball only, 3 like basketball only, 5 like all three games and 14 did not li

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Question 1178039: In a class of 50 students, 24 like football, 21 basketball and 18 cricket.
Six like football and basketball only, 3 like basketball only, 5 like all
three games and 14 did not like any of the three games
(i) Illustrate this information on a Venn diagram.
(ii) Find the number of students who like:
(α) football and cricket only;
(β) exactly one of the games.

Answer by Edwin McCravy(20056)   (Show Source): You can put this solution on YOUR website!


s = the number who like football but not basketball or cricket
t = the number who like football and basketball, but not cricket
u = the number who like basketball, but not football or cricket
v = the number who like football and cricket, but not basketball 
w = the number who like football, cricket, and basketball 
x = the number who like basketball and cricket, but not football 
y = the number who like cricket, but not football or basketball 
z = the number who did not like football, basketball, nor cricket.


5 like all three games
So w=5:


six like football and basketball only.
So t=6

3 like basketball only.
So u=3


14 did not like any of the three games
So z=14

21 liked basketball.
So t+u+w+x=21. That's
   6+3+5+x=21
      14+x=21
         x=7



24 like football.
So s+t+v+w=24
   s+6+v+5=24
    s+v+11=24
       s+v=13

18 like cricket.
So v+w+x+y=18
   v+5+7+y=18
    v+y+12=18
       v+y=6
class of 50 students
So s+t+u+v+w+x+y+z=50
   s+6+3+v+5+7+y+14=50
           s+v+y+35=50 
              s+v+y=15

Subtract        v+y=6
Get               s=9



Substitute in   s+v=13
                9+v=13
                  v=4


Substitute in   v+y=6
                4+y=6
                  y=2



(ii) Find the number of students who like:
(α) football and cricket only;
that's v=4
(β) exactly one of the games.
That's s+u+y=9+3+2=14 

Edwin


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