SOLUTION: Let U = {x ∈ Z | 0 ≤ x ≤ 20}. Also, let A = set of all even integers; B= set of all prime numbers; C = set of all numbers coprime with 2; and D={y ∈ U | y = 2z + 3, for

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Question 1167141: Let U = {x ∈ Z | 0 ≤ x ≤ 20}. Also, let A = set of all even integers;
B= set of all prime numbers; C = set of all numbers coprime with 2; and
D={y ∈ U | y = 2z + 3, for some z∈Z}.
Represent sets A, B, C, D using set-roster notation.

Answer by Edwin McCravy(20055)   (Show Source): You can put this solution on YOUR website!
U = {x ∈ Z | 0 ≤ x ≤ 20} = {0,1,2,3,...,20};

A = set of all even integers = ;

B= set of all prime numbers = ;

C = set of all numbers coprime with 2 = ;

{y ∈ U | y= 2z + 3, for some z∈Z} 

To do the last one:



Solve for z in the middle.
Subtract 3 from all three sides:



Divide all three sides by 2



Since z is an integer,

 = {-1,0,1,2,3,...,8}, substitute each 
in 2z+3:

{y ∈ U | y = 2z + 3, for some z ∈ Z} = {1,3,5,7,...,19}

Edwin

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