SOLUTION: question 1 find the value(s) of x for which ((x^3-7x^2+6x)/(x^5+4x^4-3))=0 question 2 determine the limiting value of (3n^2+1)/(4(n^2-2)) as n=∞

Question 1106383: question 1 find the value(s) of x for which
((x^3-7x^2+6x)/(x^5+4x^4-3))=0
question 2 determine the limiting value of (3n^2+1)/(4(n^2-2)) as n=∞
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
Look for values that make the numerator equal to zero.

Potential zeros: x=0, x=1, x=6.
Verify that the denominator does not equal zero for any of these potential zeros.
If it doesn't, then it's a real zero.
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SOLUTION: question 1 find the value(s) of x for which ((x^3-7x^2+6x)/(x^5+4x^4-3))=0 question 2 determine the limiting value of (3n^2+1)/(4(n^2-2)) as n=&#8734;

SOLUTION: question 1 find the value(s) of x for which ((x^3-7x^2+6x)/(x^5+4x^4-3))=0 question 2 determine the limiting value of (3n^2+1)/(4(n^2-2)) as n=∞