By Venn diagram:n(A∪B) = x + y + z = 40, n(A∩B) = y = 10 n(A) = x + y = 15 n(B) = y + z = ? So the system of equations is: (eq. 1) x + y + z = 40 (eq. 2) y = 10 (eq. 3) x + y = 15 Subtract (eq. 3) minus (eq. 2) (eq. 3) x + y = 15 -(eq. 2) -y = -10 ---------------------------------------- x = 5 Subtract (eq. 1) minus (eq. 3) (eq. 1) x + y + z = 40 -(eq. 3) -x - y = -15 ---------------------------------------- z = 25 Substitute x = 5 in (eq. 3) (eq. 3) 5 + y = 15 y = 10 n(B) = y + z = 10 + 25 = 35 ---------------------------------- By formula n(A∪B) = n(A) + n(B) - n(A∩B) 40 = 15 + n(B) - 10 40 = 5 + n(B) 35 = n(B) It's easier to use the formula, but you don't learn what's going on unless you understand the Venn diagram method. Edwin