SOLUTION: I have NO clue where to start. Give a counterexample to show the statement is not always true for real numbers a, b, & c. If a<b, then ac<bc. IF you can solve this I will be fore

SOLUTION: I have NO clue where to start. Give a counterexample to show the statement is not always true for real numbers a, b, & c. If a<b, then ac<bc. IF you can solve this I will be fore

Algebra.Com

Question 90874: I have NO clue where to start.
Give a counterexample to show the statement is not always true for real numbers a, b, & c. If a IF you can solve this I will be forever grateful.
Answer by throwabunny(3) (Show Source): You can put this solution on YOUR website!
I guess if you had 4 for a, and 5 for b, and multiplied them by -1, it wouldn't work.
Something with negatives in it.
RELATED QUESTIONS
Are these statements always, sometimes, or never true? If never, what is a... (answered by Theo)

For all integers a,b,and c, if a = b then a/c = b/c. Provide a counterexample that shows (answered by Edwin McCravy)

I sent this problem earlier but after receiving a response quickly realized I entered the (answered by jim_thompson5910,solver91311)

Determine if the following statement is always true. If it is not, provide a... (answered by tinbar)

I am trying to show the conjecture is false by finding a counterexample. The square of... (answered by stanbon)

(reasoning) consider the equation Ax+By=C a. what must be true of the equation if its... (answered by josmiceli)

(reasoning) consider the equation Ax+By=C a. what must be true of the equation if its... (answered by Fombitz)